Answer:
ammonia gas and hydrogen chloride gas.
I'm pretty sure its metals.
Answer:
0.07975 M NaOH
Explanation:
First determine the molarity of your acid, KHP. Convert grams to moles using the MW given and then divide by the volume of water.
0.3175 g KHP • (1 mol KHP / 204.2 g KHP) = 0.001555 mol KHP
0.001555 mol KHP / 0.040 L = 0.03888 M KHP
The reaction between KHP and NaOH is one-to-one, so you can just use M1V1 = M2V2 to solve for M2 (the molarity of NaOH).
M1 = 0.03888 M KHP
V1 = 40 mL
M2 = ? M NaOH
V2 = 19.45 mL NaOH
(0.03888 M KHP)(40 mL) = M2(19.5 mL NaOH)
M2 = 0.07975 M NaOH
Answer:
128g of Li, will react in this reaction
Explanation:
Before to start working, we need the reaction:
N₂ and Li react, in order to produce Li₃N (lithium nitride)
N₂ + 6Li → 2Li₃N
1 mol of nitrogen reacts with 6 moles of lithium
We convert the mass of N₂ to moles → 86.1 g . 1 mol/ 28g = 3.075 moles
1 mol of N₂ reacts with 6 mol of Li
Therefore, 3.075 moles of N₂ will react with 18.4 moles of Li
We conver the moles to mass → 18.4 mol . 6.94g / 1mol = 128 g
Answer:
Yes.
Explanation:
It will react. Because they are compounds
