Assuming 100% dissociation, calculate the freezing point and boiling point (in °C) of a solution with 83.6 g of AgNO 3 in 1.00 k
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Answer : 0.0392 grams of Zn metal would be required to completely reduced the vanadium.
Explanation :
Let us rewrite the given equations again.
On adding above equations, we get the following combined equation.
We have 12.1 mL of 0.033 M solution of VO₂⁺.
Let us find the moles of VO₂⁺ from this information.
From the combined equation, we can see that the mole ratio of VO₂⁺ to Zn is 2:3.
Let us use this as a conversion factor to find the moles of Zn.
Let us convert the moles of Zn to grams of Zn using molar mass of Zn.
Molar mass of Zn is 65.38 g/mol.
We need 0.0392 grams of Zn metal to completely reduce vanadium.
Answer:- Density is 10.5 grams per mL and the substance is Silver(Ag).
Solution:- Mass of jewelry is given as 132.6 g. Initial volume of water in the graduated cylinder is 48.6 mL and the volume becomes 61.2 mL when this jewelry is submerged in the cylinder.
So, the volume of the jewelry = 61.2 mL - 48.6mL = 12.6 mL
We know that,
Let's plug in the values in the above formula to calculate the density:
So, the density of the jewelry is .
The substance from which the jewelry is made could easily be identified by comparing the calculated density with the density values given for different substances in the density table.
Looking at the density table, 10.5 grams per mL is the density for silver. So, the jewelry is made up from Silver.