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2 years ago

75=6·w the solution is w=?

Mathematics

2 answers:

Ber [7]2 years ago

7 0

I think answer should be 450 please give me brainlest let me know if it’s correct or not okay thanks bye

scZoUnD [109]2 years ago

7 0

W＝69 75-6＝6-6+6＝W 69＝W

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3(-9) <br> please explain and answer thank u

Diano4ka-milaya [45]

Answer:

-27

Step-by-step explanation:

ok so we have (-9) in parentheses right? And positive 3 outside of parentheses so we know 9 x 3 = 27 BUT we have a negative in front of 9 so we just put -27.

Hope this helps :D ~P.s- pls could u give brainliest to meh TYSM!

5 0

3 years ago

4abc + (-9abc) + 10d?

nasty-shy [4]

-5abc+10d will be the answer.

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3 years ago

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How to write 11001195 in words

avanturin [10]

Answer:

Eleven million one thousand one hundred ninety-five

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3 years ago

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There are six teachers in a room, ages, 40, 50, 45, 55, and 65. If a 29 year old teacher enters the room, how will the mean age

klasskru [66]

The old mean was 51 now the mean is 42.33... (round that to 42) 51 - 42 = 9

7 0

3 years ago

Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

5 0

3 years ago