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dlinn [17]
3 years ago
10

Which of the following functions are continuous for all real numbers? \begin{aligned} &h(x)= \log(x) \\\\ &g(x)=\cot(x)

\end{aligned} ​ h(x)=log(x) g(x)=cot(x) ​
Mathematics
1 answer:
Mrac [35]3 years ago
5 0

Answer:

None of them.

Step-by-step explanation:

1.) h(x)=log(x) is defined only for x >0. Therefore, it can't be continous for all real numbers.

2.)

g(x)=\cot(x)=\dfrac{\cos(x)}{\sin(x)}

is not defined for x=0. Therefore, it is not contionus at 0 and so it is not continous for all real numbers.

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Xelga [282]

Answer:

10x +17y=c (C is the total cost)

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3 years ago
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How can i get the answer to 5 X 70 = 5 X ____ tens = ____ tens = _____
Maru [420]
Multiple 5x70 to get 350. Which makes the equation 350=5x and then you have to divide both sides by 5 to get x by itself.  so 5x/5 and 350/5 makes x=70
3 0
3 years ago
you are allowed to work a total of no more than 30 hours each week at your two jobs. Lawn mowing pays $5 per hour and babysittin
timama [110]

Answer:

5X + 8Y >= 300;    intersection at  (-20, 50)

Step-by-step explanation:

let t = work hours

0 < t < 30

X = time lawn mowing

Y = time babysitting.

X + Y < 30

5X + 8Y >= 300

We could solve...

X < 30 - Y

5(30 - Y) + 8Y  >=300

150 - 5Y + 8Y >= 300

3Y >=150

Y >=50

then  X < -20  

intersection at  (-20, 50)

4 0
3 years ago
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Trials in an experiment with a polygraph include 97 results that include 23 cases of wrong results and 74 cases of correct resul
o-na [289]

Answer:

H0:p= 0.80                 H1: p< 0.80  one tailed test

Step-by-step explanation:

We state the null and alternative hypotheses as that the results are 80 % against the claim that the results are less than 80%.

H0:p= 0.80                 H1: p< 0.80  one tailed test

p2= 0.8 , p1= 74/97= 0.763

q1= 1-0.763= 0.237    q2= 0.2

The level of significance is 0.05 .

The Z∝= ±1.645 for ∝= 0.05

The test statistic used here is

Z= p1-p2/ √pq/n

Putting the values:

Z= 0.763 -0.8 / √ 0.8*0.2/97

z= -0.037/ 0.0406

z= -0.9113

The Z∝ = ±1.645 for ∝= 0.05 for one tailed test.

As the calculated value  does not fall in the critical region  we fail to reject the null hypothesis. There is not sufficient evidence to support  the claim that such polygraph results are correct less than 80% of the time.

Using the normal probability table.

P (Z <  -0.9113)= 1- P(z= 0.9311) = 1- 0.8238= 0.1762

If P- value is smaller than the significance level reject H0.

0.1762> 0.005  Fail to reject H0.

8 0
3 years ago
Subtract p - q from 2p - q + 4. answer the following with explanation
ra1l [238]

Answer:

Step-by-step explanation:

2p - q + 4 - ( p - q )

2p - q + 4 - p + q

By rearranging the terms

2p - p + 4

( you might think where -q and +q went ???

They are cancelled because they have opposite signs )

∴The answer is p + 4

Hope it helps

plz mark as brainliest!!!!!!!

5 0
3 years ago
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