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3 years ago

Six less than twice a number is -22

Mathematics

1 answer:

mihalych1998 [28]3 years ago

8 0

2x-6=-22
+6 +6
2x=-16
2/2x=-16/2
x=-8
The number is -8

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The back of Dante's property is a creek. Dante would like to enclose a rectangular area, using the creek as one side and fencing

Allushta [10]

The correct value is 720 ft of fencing.

Answer:

Max Area = 64800 sq.ft

Step-by-step explanation:

A square will always give us the maximum area.

Thus, one side would be;

720/4 = 180 feet

So, we want a square 180 ft by 180 ft

however, from the question, we are to use the creek as one side. So, we'll take the 180 ft that we don't need because of the creek and then add it to the opposite side to get 180 + 180 = 360 ft.

Thus,we now have a rectangle with dimensions: 180 ft by 360 ft

Area is given by;

area = length × width

Maximum Area = 180 × 360

Max Area = 64800 sq.ft

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3 years ago

Which of the following is equivalent to 2/x + 3/x−1 for x>1 ? pls explain

Aloiza [94]

Answer:

Step-by-step explanation:

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2 years ago

Make v the subject of the formula T = v/6 -5

OverLord2011 [107]

Answer:

Step-by-step explanation:

T=V/6-5

T+5=V/6

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2 years ago

Based on a study of population projections for 2000 to 2050, the projected population of a group of people (in millions) can b

Olegator [25]

Answer:

(a) 0.107 million per year

(b) 0.114 million per year

Step-by-step explanation:

$A(t) = 11.19(1.009)^t$

(a) The average rate of change between 2000 and 2014 is determined by dividing the difference in the populations in the two years by the number of years. In the year 2000, $t=0$ and in 2014, $t=14$ . Mathematically,

$\text{Rate}=\dfrac{A(2014) - A(2000)}{2014-2000}=\dfrac{11.19(1.009)^14-11.19(1.009)^0} {14}$

$A(0)=\dfrac{12.69-11.19}{14}=\dfrac{1.5}{14}=0.107$

(b) The instantaneous rate of change is determined by finding the differential derivative at that year.

The result of differentiating functions of the firm $y=a^x$ (where $a$ is a constant) is $\dfrac{dy}{dx}=a^x\ln a$ . Let's use in this in finding the derivative of $A(t)$ .