Your first point should always be shown in the y-intercept following the standard form for slope-intercept form
Y = mx + b
b = y - intercept
In this case your first point would be (0,1)
You next point would be following the slope which is -2x. When you graph a equation always know that it is rise over run. For this line, it would be going from left to right since it is a negative line.
Your second point would go down 2 points from your starting point (0,1) and run 1 to the right in the x-axis, which is also called, (1,-3)
False, it does not change the shape of the figure, it only changes the size
56° and 34°
complementary angles sum to 90° thus
3x - 10 + 2x - 10 = 90
5x - 20 = 90
add 20 to both sides of the equation
5x = 90 + 20 = 110
divide both sides by 5
x = = 22
angle 2x - 10 = (2 × 22) - 10 = 44 - 10 = 34° and
angle 3x - 10 = (3 × 22) - 10 = 66 - 10 = 56°
Answer:
(x-7) (x+4)
Step-by-step explanation:
x^2 - 3x - 28
What two numbers multiply to -28 and add to -3
-7*4 = -28
-7+4 = -3
(x-7) (x+4)
Answer:
is outside the circle of radius of centered at .
Step-by-step explanation:
Let and denote the center and the radius of this circle, respectively. Let be a point in the plane.
Let denote the Euclidean distance between point and point .
In other words, if is at while is at , then .
Point would be inside this circle if . (In other words, the distance between and the center of this circle is smaller than the radius of this circle.)
Point would be on this circle if . (In other words, the distance between and the center of this circle is exactly equal to the radius of this circle.)
Point would be outside this circle if . (In other words, the distance between and the center of this circle exceeds the radius of this circle.)
Calculate the actual distance between and :
.
On the other hand, notice that the radius of this circle, , is smaller than . Therefore, point would be outside this circle.