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Alexxx [7]
4 years ago
11

xFormula1" title="x {}^{2} + 140 \times + 2400 = 6 \times " alt="x {}^{2} + 140 \times + 2400 = 6 \times " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
ipn [44]4 years ago
3 0
Can you write it normally lol

Fr just use photomath
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Lebron James and Steph Curry went up against each other in the NBA finals. Lebron scored 2 points every 3 minutes, and Curry sco
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curry would have more

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the reason is because if you divide 3 by 2 it give you 1.5 you multiple that by 48 which is 72 and then you do the same thing to curry and curry approximately 77 points in 48 minutes

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Find the volume of the solid bounded by the plane z = 0 and the paraboloid z = 1 - x2 - y2. SOLUTION If we put z = 0 in the equa
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3

Step-by-step explanation:

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Find the value of 'a' in the equation
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. Write a word problem that can be acted out using these counters.
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3 years ago
Suppose we have 3 cards identical in form except that both sides of the first card are colored red, both sides of the second car
Nikolay [14]

Answer:

probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3

Step-by-step explanation:

First of all;

Let B1 be the event that the card with two red sides is selected

Let B2 be the event that the

card with two black sides is selected

Let B3 be the event that the card with one red side and one black side is

selected

Let A be the event that the upper side of the selected card (when put down on the ground)

is red.

Now, from the question;

P(B3) = ⅓

P(A|B3) = ½

P(B1) = ⅓

P(A|B1) = 1

P(B2) = ⅓

P(A|B2)) = 0

(P(B3) = ⅓

P(A|B3) = ½

Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;

P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]

Thus;

P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]

P(B3|A) = (1/6)/(⅓ + 0 + 1/6)

P(B3|A) = (1/6)/(1/2)

P(B3|A) = 1/3

5 0
3 years ago
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