Let d represent the distance of the destination from the starting point.
After 45 min, Henry has already driven d-68 miles. After 71 min., he has already driven d-51.5 miles.
So we have 2 points on a straight line:
(45,d-68) and (71,d-51.5). Let's find the slope of the line thru these 2 points:
d-51.5 - (d-68) 16.5 miles
slope of line = m = ----------------------- = ------------------
71 - 45 26 min
Thus, the slope, m, is m = 0.635 miles/min
The distance to his destination would be d - (0.635 miles/min)(79 min), or
d - 50.135 miles. We don't know how far his destination is from his starting point, so represent that by "d."
After 45 minutes: Henry has d - 68 miles to go;
After 71 minutes, he has d - 51.5 miles to go; and
After 79 minutes, he has d - x miles to go. We need to find x.
Actually, much of this is unnecessary. Assuming that Henry's speed is 0.635 miles/ min, and knowing that there are 8 minutes between 71 and 79 minutes, we can figure that the distance traveled during those 8 minutes is
(0.635 miles/min)(8 min) = 5.08 miles. Subtracting thix from 51.5 miles, we conclude that after 79 minutes, Henry has (51.5-5.08), or 46.42, miles left before he reaches his destination.
Answer: 48
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Define the number of cakes they baked in term of x
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Let the number of cakes Kay baked be x
Kay = x
Tim = 3x ← Tim baked 3 times as many as Kay
Griff = 1.5x ← Griff baked 1/2 as many as Tim
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Construct the equation and solve for x
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The total number of cakes baked was 88.
x + 3x + 1.5x = 88 ← Combine like terms
5.5 x = 88 ← Divide by 5.5
÷5.5 ÷5.5
x = 16
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Find the number of cakes each baked
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Kay = x = 16
TIm = 3x = 16 x 3 = 48
Griff = 1.5x = 1.5(16) = 24
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Answer: Tim baked 48 cakes.
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Answer:
11.x=16 12.x=37
Step-by-step explanation:
11.
20^2-12^2=x^2
256=x^2
x=√256
x=16
12.
13^2-5^2=y^2
144=y^2
y=12
/
y^2+35^2=x^2
12^2+35^2=x^2
1369=x^2
x=37
Answer:
x=17
Step-by-step explanation:
