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MrRissso [65]
2 years ago
9

Evaluate (−23)×(−23)3 by using the Laws of Exponents

Mathematics
1 answer:
Nikolay [14]2 years ago
3 0

Given:

\left(-\dfrac{2}{3}\right)\times \left(-\dfrac{2}{3}\right)^3

To find:

The value of given expression by using the Laws of Exponents.

Solution:

We have,

\left(-\dfrac{2}{3}\right)\times \left(-\dfrac{2}{3}\right)^3

Using the Laws of Exponents, we get

=\left(-\dfrac{2}{3}\right)^{1+3}      [\because a^ma^n=a^{m+n}]

=\left(\dfrac{-2}{3}\right)^{4}

=\dfrac{(-2)^4}{(3)^4}      [\because \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}]

=\dfrac{(-2)\times (-2)\times (-2)\times (-2)}{(3)\times (3)\times (3)\times (3)}

=\dfrac{16}{81}

Therefore, the value of given expression is \dfrac{16}{81}.

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