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Mars2501 [29]
3 years ago
15

In a lottery game, a player picks six numbers from 1 to 22. If the player matches all six numbers, they win 20,000 dollars. Othe

rwise, they lose $1.
What is the expected value of this game?
Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
8 0

Answer:

Total possible number of outcomes = C(24,6) [24 choose 6]

=24!/(6!18!)

= 134596

Out of which there is only one winning combination.

Therefore we conclude:

P(win 20000)=1/134596

P(lose 1)=134595/134596

and hence the expected value is:

20000*(1/134596)+(-1)*(134595/134596)

=-114595/134596

=-0.8514 (rounded to four places after decimal)

Step-by-step explanation:

Hope this helped!

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in the year 2001, a person bought a new car for $22000. for each consecutive year after that, the value of the car depreciated b
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Answer:

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Step-by-step explanation:

Firstly, we need to write the depreciation equation

We have this as:

V = I(1 - r)^t

V is the present value which is what we want to calculate

I is the initial value, the amount the cad was bought which is $22,000

r is the rate of change which is 5% = 5/100 = 0.05

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7 0
3 years ago
Find x and the measure of each side.
Anna71 [15]

Answer:

x=27.5

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HF=47.5

Step-by-step explanation:

Sum of angles in a triangle=180

Therefore, FG+GH+HF=180

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(3x - 10) + (2x+5) +(x+20) = 180

Collecting like terms

3x+2x+x = 180 +10 - 5 - 20

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X= 27.5

FG = (3x - 10) = 3(27.5) - 10

FG= 72.5

GH= (2x+5) = 2(27.5)+5

GH=60

HF= x+20 =27.5+20

HF=47.5

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Step-by-step explanation:

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Step-by-step explanation:

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