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Mars2501 [29]
2 years ago
15

In a lottery game, a player picks six numbers from 1 to 22. If the player matches all six numbers, they win 20,000 dollars. Othe

rwise, they lose $1.
What is the expected value of this game?
Mathematics
1 answer:
Angelina_Jolie [31]2 years ago
8 0

Answer:

Total possible number of outcomes = C(24,6) [24 choose 6]

=24!/(6!18!)

= 134596

Out of which there is only one winning combination.

Therefore we conclude:

P(win 20000)=1/134596

P(lose 1)=134595/134596

and hence the expected value is:

20000*(1/134596)+(-1)*(134595/134596)

=-114595/134596

=-0.8514 (rounded to four places after decimal)

Step-by-step explanation:

Hope this helped!

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x = 1.5

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y=3x+2

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we have m here so

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2 years ago
The Moores paid $6 more for skate rentals than the Cotters did. Together, the two families paid $30 for skate rentals.How many p
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Answer:

Step-by-step explanation:

Consider Cotters paid "x" dollars:

According to given condition:

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2x +6 = 30

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3 0
3 years ago
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I hope this helps you

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CAN SOMEONE PLEASE HELP ME???<br> ↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓
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Answer:

Option D, AP

Step-by-step explanation:

<u>The two sides that are connected by the right angle are called the sides.  The longest one that is not connect with a right angle is called the hypotenuse.</u>

<u />

In this case, the sides are AZ and PZ.  <em>The hypotenuse is AP</em>

<em />

Answer:  Option D, AP

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