Answer:
Step-by-step explanation:
= Surface area of base = 5 square meters
Volume of water in tank = 70 cubic meters
The rate at which the volume is reducing is
Integrating from 
to 
Volume of water remaining in the tank is 
Suface area of base 
depth = Volume
The depth of the water remaining in the tank is .
Answer:
D) 57
Step-by-step explanation:
1/3x- 1/2 = 18 1/2
1/3x = 19
(3) * 1/3x = 19 (3)
x = 57
Answer:
S varies partly directly as M and Q.
S=C.
S=KMQ+C.
For the first one...
speed=80,m=220,Q=30.
80=K20×30+C.
80=600K+C......(I).equation one.
For the second one....
speed=60,m=300,Q=40.
60=K300×40+C.
60=12000K+C.....(ii). equation two.
Minus eqtn(I) from eqtn(ii).
80=600K+C.
- 60=12000K+C.
K=0.01754~0.018.
Substitute K=0.018 into eqtn(I).
80=600K+C
80=600×0.018+C.
80=10.8+C.
C=80-10.8=69.2.
The relation is S=0.018MQ+69.2
when speed is 100 and mass is 250 find the volume.
100=0.018×250×Q+69.2.
100=4.5Q+69.2.
4.5Q=100-69.2
4.5Q=30.8.
Q=30.8/4.5.
Q=6.8~7litres.
1 ton is equivalent to 2000 pounds
we have to find how many pounds 3 3/8 tons are equal to
if 1 ton --> 2000 pounds
we can break down the fraction into 3 + 3/8
then 3 tons --> 2000 x 3 = 6000 pounds
3/8 ton ---> 2000 x 3/8 = 
after adding 6000 + 750 = 6750 pounds
answer is 6750 pounds
<h2>Long short story: I tried ;-; </h2>
