In order to utilize the graph, first you have to distinguish which graph accurately pertains to the two functions.
This can be done by rewriting the equations in the form y = mx + b which can be graphed with ease; where m is the slope and b is the y intercept.
-x^2 + y = 1
y = x^2 + 1
So this will be a basic y = x^2 parabola where the center intercepts on the y axis at (0, 1)
-x + y = 2
y = x +2
So this will be a basic y = x linear where the y intercept is on the y axis at (0, 2)
The choice which depicts these two graphs correctly is the first choice. The method to find the solutions to the system of equations by using the graph is by determining the x coordinate of the points where the two graphed equations intersect.
I believe the correct answer from the choices listed above is the first option. If the sides of a square are five to the power of two fifths inches long, then the are of the square would be <span>five to the power of four fifths square inches. Hope this answers the question.</span>
Example:
38 rounds to 40
6 rounds to 10
10+40 = 50
Answer:
Option D
Step-by-step explanation:
Given f(x) = ![\sqrt[3]{4x}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B4x%7D)
g(x) = 2x + 3
Since, 
![=\frac{\sqrt[3]{4x}}{2x+3}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5Csqrt%5B3%5D%7B4x%7D%7D%7B2x%2B3%7D)
This function is defined for the denominator is not equal to zero.
(2x + 3) ≠ 0
x ≠ 
Therefore, Option D will be the correct option.
