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sp2606 [1]
3 years ago
8

Plz help me anyone fast I have 10 min

Mathematics
1 answer:
Yuki888 [10]3 years ago
3 0

Answer:

sorry i  am in 7th grade

Step-by-step explanation:

sooooooooooooooooooooooooooooooooooooorrrrrrrrrrrrrrrrrrrrrrrrrrrryyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy

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At work, Brett must check and record the internal temperature of the freezer on an hourly basis. When working properly, the temp
antoniya [11.8K]

Answer:

B. zero

Step-by-step explanation:

If the temperature is supposed to remain constant over time (the same) when working properly, then this means that there is no increase or decrease over time.

If there were a line to represent this, then it would be a straight line with a slope of 0 because the temperature would remain the same.

4 0
3 years ago
PLEASE HELP ME i DONT KNOW how to do this!​
ra1l [238]

Answer:

It's b

Step-by-step explanation:

It is b or the second option because -2 is equal or greater than A therefore it is option 2

7 0
3 years ago
Read 2 more answers
Would the answer be A ) 15 or B ) 18?
Stels [109]
Your answer is (A 15)
6 0
3 years ago
Inequality <br> Choose all answers that apply
maxonik [38]

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

Option A;  m \leq\frac{3}{5}

»»————- ★ ————-««  

Here’s why:  

  • We can use inverse operations to solve for 'm'.

⸻⸻⸻⸻

\boxed{\text{Solving for 'm':}}\\\\5m+1\leq4\\--------\\\rightarrow 5m + 1 - 1 \leq 4 - 1\\\\\rightarrow 5m\leq3\\\\\rightarrow \frac{5m\leq3}{5}\\\\\rightarrow \boxed{m\leq\frac{3}{5}}

⸻⸻⸻⸻

Any number that is less than or equal to the value of three-fifths would work.

The option that is less than or equal to (3/5) is option A.

Assuming that there are more options than the options shown, choose the numbers that are less than or equal to (3/5).

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

8 0
3 years ago
The quantity a varies directly with b and c and inversely with dThe quantity d is tripledWhich of the following must be true for
EastWind [94]

Answer:

We have the next relation:

A = (b*d)/c

because we have direct variation with b and d, but inversely variation with c.

Now, if we have 3d instead of d, we have:

A' = (b*(3d))/c

now, we want A' = A. If b,c, and d are the same in both equations, we have that:

3bd/c = b*d/c

this will only be true if b or/and d are equal to 0.

If d remains unchanged, and we can play with the other two variables we have:

3b'd/c' = bd/c

3b'/c' = b/c

from this we can took that: if c' = c, then b' = b/3, and if b = b', then c' = 3c.

Of course, there are other infinitely large possible combinations that are also a solution for this problem where neither b' = b or c' = c

6 0
3 years ago
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