Answer:
x=0.3 0r x=3/10
Step-by-step explanation:
Answer:
Step-by-step explanation:
Hello!
To test if boys are better in math classes than girls two random samples were taken:
Sample 1
X₁: score of a boy in calculus
n₁= 15
X[bar]₁= 82.3%
S₁= 5.6%
Sample 2
X₂: Score in the calculus of a girl
n₂= 12
X[bar]₂= 81.2%
S₂= 6.7%
To estimate per CI the difference between the mean percentage that boys obtained in calculus and the mean percentage that girls obtained in calculus, you need that both variables of interest come from normal populations.
To be able to use a pooled variance t-test you have to also assume that the population variances, although unknown, are equal.
Then you can calculate the interval as:
[(X[bar]_1-X[bar_2) ±
*
]


[(82.3-81.2) ± 1.708* (6.11*
]
[-2.94; 5.14]
Using a 90% confidence level you'd expect the interval [-2.94; 5.14] to contain the true value of the difference between the average percentage obtained in calculus by boys and the average percentage obtained in calculus by girls.
I hope this helps!
Oma made a mistake in step B, because she should have divided both sides by b instead of just moving it to the other side. The real next step would look like:
(2A)/b=h
Answer:
i think u add 2.5 everytime
Step-by-step explanation:
for example start with(0, 2.5) 0n the graph then add 2.5 to 2.5 then keep adding if im wrong srry
Answer:
So first we have 10x = 0. We divide by 10 on both sides, so then we get x = 0. We still have 0 because 0/10 = 0.
So that means that the answer is
<h2><u>
Write 10 in the first box 10 in the second</u></h2><h2><u>
x=0</u></h2>