Answer:
Richhhh!!! Thanks for the points!!
Step-by-step explanation:
Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].
Answer:
x = 2
Step-by-step explanation:
6x-1=11
Add 1 to each side
6x-1+1=11+1
6x = 12
Divide by 6
6x/6 = 12/6
x = 2
Answer:
see below
Step-by-step explanation:
{(x, y) : x≥2}∩{(x, y) : y≥2}
First {(x, y) : x≥2}
A solid line at x =2 and shaded to the right
(x, y) : y≥2
A solid line at y =2 and shaded above
∩ means intersection or where they overlap
The green area is where they over lap