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levacccp [35]
2 years ago
13

HELP DUE IN 10 MINS!

Mathematics
1 answer:
Scilla [17]2 years ago
3 0

Answer:

\checkmark \text{B. The area of the circle is } 729\pi,\\\checkmark \text{D. The arc length of the sector is } 12\pi

Step-by-step explanation:

Area of a circle with radius r: r^2\pi

Circumference of a sector with radius r: 2r\pi

Area of sector with angle \theta:  r^2\pi\cdot \frac{\theta}{360}.

Arc length of sector with angle \theta: 2r\pi\cdot \frac{\theta}{360}

Using these equations, we get the following information:

Area of circle: 27^2\pi=729\pi

Circumference of a circle: 2\cdot 27\cdot \pi=54\pi

Area of sector: 27^2\pi\cdot \frac{80}{360}=162\pi

Arc length of sector: 2\cdot 27\cdot \pi \cdot \frac{80}{360}=12\pi

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Need help with this struggling a bit.
Kaylis [27]
The answer is A hope it helps plz mark me a brainlest
6 0
2 years ago
Read 2 more answers
I need help! This is 8 points!
Solnce55 [7]

Answer:

nope

Step-by-step explanation:

there are same sizes fine but the breadth isn't the same

5 0
2 years ago
3. What are the roots of the polynomial y = x³ - 8?
zzz [600]

Step-by-step explanation:

x^3 is a perfect cube, 8 is a perfect cube, so we use difference of cubes.

{a}^{3}  -  {b}^{3}  = (a - b)( {a}^{2}  + ab +  {b}^{2} )

Cube root of x^3 is x.

Cube root of 8 is 2

So

a=x

b= 2.

(x - 2)( {x}^{2}  - 2x + 4)

Set these equations equal to zero

x - 2 = 0

x = 2

{x}^{2}  - 2x + 4 = 0

If we do the discriminant, we get a negative answer so we would have two imaginary solutions,

Thus the only real root is 2.

If you want imaginary solutions, apply the quadratic formula.

1 + i  \sqrt{ 3 }

and

1 - i \sqrt{3}

4 0
1 year ago
Someeee one?????????????????
Ad libitum [116K]

Answer:

Option B) a_{n} = 2\cdot 4^{n-1}

Step-by-step explanation:

The given geometric sequence is

2, 8, 32, 128,....

The general form of a geometric sequence is given by

a_{n} = a_{1}\cdot r^{n-1}

Where n is the nth term that we want to find out.

a₁ is the first term in the geometric sequence that is 2

r is the common ratio and can found by simply dividing any two consecutive numbers in the sequence,

r=\frac{8}{2} = 4

You can try other consecutive numbers too, you will get the same common ratio

r=\frac{32}{8} = 4

r=\frac{128}{32} = 4

So the common ratio is 4 in this case.

Substitute the value of a₁ and r into the above general equation

a_{n} = 2\cdot 4^{n-1}

This is the general form of the given geometric sequence.

Therefore, the correct option is B

Note: Don't multiply the first term and common ratio otherwise you wont get correct results.

Verification:

a_{n} = 2\cdot 4^{n-1}

Lets find out the 2nd term

Substitute n = 2

a_{2} = 2\cdot 4^{2-1} = 2\cdot 4^{1} = 2\cdot 4 = 8

Lets find out the 3rd term

Substitute n = 3

a_{3} = 2\cdot 4^{3-1} = 2\cdot 4^{2} = 2\cdot 16 = 32

Lets find out the 4th term

Substitute n = 4

a_{4} = 2\cdot 4^{4-1} = 2\cdot 4^{3} = 2\cdot 64 = 128

Lets find out the 5th term

Substitute n = 5

a_{5} = 2\cdot 4^{5-1} = 2\cdot 4^{4} = 2\cdot 256 = 512

Hence, we are getting correct results!

6 0
3 years ago
If f(x)=x+8 and g(x)=-4-3 find (f+g)(x)
Lilit [14]

Answer:

(f+g)(x) = -3x+5

Step-by-step explanation:

f(x)=x+8 and g(x)=-4x-3

(f+g)(x) = f(x) + g(x)

             = x+8+-4x-3

             = -3x+5

3 0
3 years ago
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