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Bingel [31]
3 years ago
5

7. Rose can type 70 words per minute (wpm). At this rate, how many words can she type in 30 minutes? a. 3100 wpm b. 40 wpm c. 21

00 wpm d. 280 wpm​
Mathematics
1 answer:
Irina-Kira [14]3 years ago
3 0

Answer:

a. 3100 wpm

1 \: minute = 70 \: words \\ 30 \: minutes  = (30 \times 70) \: words \\  = 2100 \: words

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5x + 10 &gt; 35<br> How do you work this out?
Alexxx [7]

Answer:

x > 5

Step-by -step explanation:

Solving inequalities is similar to solving equations.

5x + 10 > 35

Subtract 10 from both sides.

5x > 25

Divide by 5 from both sides to isolate the x.

x > 5

3 0
3 years ago
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Need help I don’t know what he did wrong
Naddik [55]

Answer:

6-2x+5+4x

Group the similar numbers

2x+11

Step-by-step explanation:

Tyler multiplied the numbers when he should've have grouped the similar numbers together

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3 years ago
Suppose each of the following data sets is a simple random sample from some population. For each dataset, make a normal QQ plot.
adell [148]

Answer:

a) For this case the histogram is not too skewed and we can say that is approximately symmetrical so then we can conclude that this dataset is similar to a normal distribution

b) For this case the data is skewed to the left and we can't assume that we have the normality assumption.

c) This last case the histogram is not symmetrical and the data seems to be skewed.

Step-by-step explanation:

For this case we have the following data:

(a)data = c(7,13.2,8.1,8.2,6,9.5,9.4,8.7,9.8,10.9,8.4,7.4,8.4,10,9.7,8.6,12.4,10.7,11,9.4)

We can use the following R code to get the histogram

> x1<-c(7,13.2,8.1,8.2,6,9.5,9.4,8.7,9.8,10.9,8.4,7.4,8.4,10,9.7,8.6,12.4,10.7,11,9.4)

> hist(x1,main="Histogram a)")

The result is on the first figure attached.

For this case the histogram is not too skewed and we can say that is approximately symmetrical so then we can conclude that this dataset is similar to a normal distribution

(b)data = c(2.5,1.8,2.6,-1.9,1.6,2.6,1.4,0.9,1.2,2.3,-1.5,1.5,2.5,2.9,-0.1)

> x2<- c(2.5,1.8,2.6,-1.9,1.6,2.6,1.4,0.9,1.2,2.3,-1.5,1.5,2.5,2.9,-0.1)

> hist(x2,main="Histogram b)")

The result is on the first figure attached.

For this case the data is skewed to the left and we can't assume that we have the normality assumption.

(c)data = c(3.3,1.7,3.3,3.3,2.4,0.5,1.1,1.7,12,14.4,12.8,11.2,10.9,11.7,11.7,11.6)

> x3<-c(3.3,1.7,3.3,3.3,2.4,0.5,1.1,1.7,12,14.4,12.8,11.2,10.9,11.7,11.7,11.6)

> hist(x3,main="Histogram c)")

The result is on the first figure attached.

This last case the histogram is not symmetrical and the data seems to be skewed.

7 0
3 years ago
Which expression represents the distance between 4.7 and −11.2 on the number line?
Cerrena [4.2K]

Answer:

4.7 - ( -11.2)

Step-by-step explanation:

4.7 - ( - 11.2) = 15.9  

15.9 is the distance between 4.7 and -11.2

Hopefully this helps you

pls mark brainlest

3 0
3 years ago
What's the Answer ~ <br><br><img src="https://tex.z-dn.net/?f=%20%5Csf%20%5Ctiny%7B14%20%20%2B%20%2014%20%5Cdiv%207%7D" id="TexF
butalik [34]

Step-by-step explanation:

remember the priorities of the different mathematical operations

1. brackets

2. exponents

3. multiplications and divisions

4. additions and subtractions

so,

14 + 14/7 = 14 + 2 = 16

8 0
2 years ago
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