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Pie
2 years ago
9

A portion of a field has drained more rapidly than the rest, leading to drought conditions in that area several days before the

water was needed in the rest of the field
Biology
1 answer:
Andrew [12]2 years ago
3 0

Answer:

Due to sloppy nature of the field.

Explanation:

This problem of rapidly drainage can be solved if the field should leveled because the portion is rapidly drained due to sloppy nature of the field. Sloppy nature of land moves water at the faster rate from higher elevation to lower elevation. We can see in tillage practices, the farmers used levelers in order to level the field in order to provide even resources such as fertilizers and water. So we can say that this problem can be solved if the field will be leveled.

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The answer is 51.0 ml but can someone explain why please
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Answer:

\boxed{\sf A. \ 51 \ mL}

Explanation:

Amount of water displaced by the sphere will be equal to the volume of complete sphere.

As the sphere completely sinks to the bottom of the cup.

We have been given;

Diameter of sphere (d) = 4.6 cm

So,

\sf Radius \:  of \:  sphere  \: (r) =  \frac{Diameter \:  of \:  sphere \: (d)}{2}  \\  \sf =  \frac{4.6}{2}  \\ \sf  = 2.3 \: cm

Volume of sphere (V):

\boxed{ \bold{V =  \frac{4}{3} \pi {r}^{3} }}

By substituting value of r we get:

\sf \implies V =  \frac{4}{3}  \times \pi \times  {(2.3)}^{3}  \\  \\  \sf \implies V =  \frac{4}{3}  \times 3.14 \times 12.167 \\  \\ \sf \implies V =    \frac{152.81752}{3} \\  \\   \sf \implies V =  50.94 \:  {cm}^{3}  \\  \\   \sf \implies V  \approx 51 \:  {cm}^{ 3}

1 cm³ = 1 mL

\therefore

V = 51 mL

So,

Water displaced by the sphere = 51 mL

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