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8090 [49]
3 years ago
11

I need help ASAP PLEASE PLEASE HELP

Mathematics
1 answer:
sp2606 [1]3 years ago
4 0

Answer:

4

Step-by-step explanation:

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Consider this sphere with a diameter of 5 m.
abruzzese [7]

Answer: only C and E

Step-by-step explanation:

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3 years ago
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The volleyball team sold 16 items on the first day of a bake sale, 28 items the second day, and 12 items the last day. There wer
Marrrta [24]
16+28+12=56

56+4=60

There were 60 total items for sale at the bake sale.
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3 years ago
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Geri believed the answer to one of her homework problems was 2 cubed. After checking her work, she realized the correct answer w
TiliK225 [7]

Answer:

The correct answer is 64 times Geri’s original answer

Step-by-step explanation:

Given

Gari's Answer: 2³

Correct Answer: 2⁹

Required:

Relationship between both answers

Let Gari's answer be represented by G and the Correct answer be represented by C; Such that

G = 2³

C = 2⁹

Divide C by G

\frac{C}{G} = \frac{2^9}{2^3}

From law of indices, \frac{a^m}{a^n} = a^{m-n}

Applying this law, we have

\frac{C}{G} = 2^{9-3}

\frac{C}{G} = 2^{6}

\frac{C}{G} = 2*2*2*2*2*2

\frac{C}{G} = 64

Multiply both sides by G

G * \frac{C}{G} = 64 * G

C = 64G

Hence, we can conclude that the correct answer is 64 times Geri’s original answer

4 0
3 years ago
Read 2 more answers
What is -2n - 24 = -8(2n-4) , and how do I do it? Thanks in advance.
myrzilka [38]
-2n-24=-8(2n-4)
Multiply both sides by -1
2n+24=8(2n-4)
Distribute the right side
2n+24=16n-32
Subtract 2n from both sides
24=14n-32
Add 32 to both sides
56=14n
Divide 14 from both sides
n=4
7 0
3 years ago
Read 2 more answers
Evaluate the function at the indicated values if possible. If an indicated value is not in the​ domain, say so.
goldfiish [28.3K]

Answer:

f(-7)=0.

f(2)=-9/5.

f(3) doesn't exist because 3 isn't in the domain of the function.

Step-by-step explanation:

f(x)=\frac{x+7}{x^2-9} is the given function.

We are asked to find:

f(-7)

f(2)

f(3).

f(-7) means to replace x in the expression called f with -7:

Evaluate \frac{x+7}{x^2-9} at x=-7

\frac{(-7)+7}{(-7)^2-9}

\frac{0}{49-9}

\frac{0}{40}

0

So f(-7)=0.

f(2) means to replace x in the expression called f with 2:

Evaluate \frac{x+7}{x^2-9} at x=2

\frac{2+7}{2^2-9}

\frac{9}{4-9}

\frac{9}{-5}

\frac{-9}{5}

So f(2)=-9/5

f(3) means to replace x in the expression called f with 3:

Evaluate \frac{x+7}{x^2-9} at x=3

\frac{3+7}{3^2-9}

\frac{10}{9-9}

\frac{10}{0}

Division by 0 is not allowed so 3 is not in the domain of our function.

5 0
3 years ago
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