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3 years ago

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I need help ASAP PLEASE PLEASE HELP

1 answer:

sp2606 [1]3 years ago

4 0

Answer:

4

Step-by-step explanation:

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Consider this sphere with a diameter of 5 m.

abruzzese [7]

Answer: only C and E

Step-by-step explanation:

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3 years ago

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The volleyball team sold 16 items on the first day of a bake sale, 28 items the second day, and 12 items the last day. There wer

Marrrta [24]

16+28+12=56

56+4=60

There were 60 total items for sale at the bake sale.

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3 years ago

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Geri believed the answer to one of her homework problems was 2 cubed. After checking her work, she realized the correct answer w

TiliK225 [7]

Answer:

The correct answer is 64 times Geri’s original answer

Step-by-step explanation:

Given

Gari's Answer: 2³

Correct Answer: 2⁹

Required:

Relationship between both answers

Let Gari's answer be represented by G and the Correct answer be represented by C; Such that

G = 2³

C = 2⁹

Divide C by G

$\frac{C}{G} = \frac{2^9}{2^3}$

From law of indices, $\frac{a^m}{a^n} = a^{m-n}$

Applying this law, we have

$\frac{C}{G} = 2^{9-3}$

$\frac{C}{G} = 2^{6}$

$\frac{C}{G} = 2*2*2*2*2*2$

$\frac{C}{G} = 64$

Multiply both sides by G

$G * \frac{C}{G} = 64 * G$

$C = 64G$

Hence, we can conclude that the correct answer is 64 times Geri’s original answer

4 0

3 years ago

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What is -2n - 24 = -8(2n-4) , and how do I do it? Thanks in advance.

myrzilka [38]

-2n-24=-8(2n-4)
Multiply both sides by -1
2n+24=8(2n-4)
Distribute the right side
2n+24=16n-32
Subtract 2n from both sides
24=14n-32
Add 32 to both sides
56=14n
Divide 14 from both sides
n=4

7 0

3 years ago

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Evaluate the function at the indicated values if possible. If an indicated value is not in the domain, say so.

goldfiish [28.3K]

Answer:

f(-7)=0.

f(2)=-9/5.

f(3) doesn't exist because 3 isn't in the domain of the function.

Step-by-step explanation:

$f(x)=\frac{x+7}{x^2-9}$ is the given function.

We are asked to find:

$f(-7)$

$f(2)$

$f(3)$ .

f(-7) means to replace x in the expression called f with -7:

Evaluate $\frac{x+7}{x^2-9}$ at $x=-7$

$\frac{(-7)+7}{(-7)^2-9}$

$\frac{0}{49-9}$

$\frac{0}{40}$

$0$

So f(-7)=0.

f(2) means to replace x in the expression called f with 2:

Evaluate $\frac{x+7}{x^2-9}$ at $x=2$

$\frac{2+7}{2^2-9}$

$\frac{9}{4-9}$

$\frac{9}{-5}$

$\frac{-9}{5}$

So f(2)=-9/5

f(3) means to replace x in the expression called f with 3:

Evaluate $\frac{x+7}{x^2-9}$ at $x=3$

$\frac{3+7}{3^2-9}$

$\frac{10}{9-9}$

$\frac{10}{0}$

Division by 0 is not allowed so 3 is not in the domain of our function.

5 0

3 years ago