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Mekhanik [1.2K]
3 years ago
15

2.12.5: Four Corners

Engineering
1 answer:
PtichkaEL [24]3 years ago
3 0

Answer:

speed(0)

square_length = int(input("What is the length of the square?"))

def draw_square():

   pendown()

   for i in range(4):

       forward(square_length)

       left(90)

   penup()

   

penup()

setposition(-200, -200)

draw_square()

penup()

setposition(-200, 200 - square_length)

draw_square()

penup()

setposition(200 - square_length, 200 - square_length)

draw_square()

penup()

setposition(200 - square_length, -200)

draw_square()Explanation:

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Two concentric helical compression springs made of steel and having the same length when loaded and when unloaded are used to su
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Answer:

see explaination for all the answers and full working.

Explanation:

deflection=8P*DN/Gd^4

G(for steel)=70Gpa=70*10^9N/m^2=70KN/mm^2

for outer spring,

deflection=8*3*50^3*5/(70*9^4)=32.66mm

for inner spring

deflection=8*3*30^3*10/(70*5^4)=148.11mm

max stress=k*8*P*C/(3.14*d^2)

for outer spring

c=50/9=5.55

k=(4c-1/4c-4)+.615/c=1.2768

max stress=1.2768*8*3*5.55/(3.14*9^2=.66KN.mm^2

for inner spring

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6 0
4 years ago
Read 2 more answers
Air enters the combustor of a jet engine at p1=10 atm, T1=1000°R, and M1=0.2. Fuel is injected and burned, with a fuel/air mass
snow_lady [41]

Answer:

M2 = 0.06404

P2 = 2.273

T2 = 5806.45°R

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Given that p1 = 10atm, T1 = 1000R, M1 = 0.2.

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F/A =???? = FA slugf/slugaq = 4.5 x 108ft-lb/slugfx FA slugf/sluga = (4.5 x 108)FA ft-lb/sluga

For the air q = cp(To2– To1)

(Exit flow – inlet flow) – choked flow is assumed For M1= 0.2

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T/T* = 0.2066,

To/To* = 0.1736 To* = To2= To/0.1736 = 1008/0.1736 = 5806.45 ºR Gives q = cp(To* - To) = (6006 ft-lb/sluga-ºR)*(5806.45 – 1008)ºR = 28819500 ft-lb/slugaSetting equal to equation 1 above gives 28819500 ft-lb/sluga= FA*(4.5 x 108) ft-lb/slugaFA =

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3 years ago
An oil reservoir has a average porosity of 20%, an area of 100 acres, and a av- erage thickness of 10 feet. The connate water sa
hram777 [196]

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= 620640 bbl x 5.609

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This is a very very difficult one for me, let me get back to you with the proper answer.
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