9514 1404 393
Answer:
C. The zeros are -1 and 5/2, because f(x) = (x + 1)(2x-5).
Step-by-step explanation:
The zeros of the function are the values that make the factors zero. The factors need to multiply out to give the original standard-form equation.
The sign of the constant (-5) tells you the product of the constants in the factors must be -5. That is only true for choices B and C.
Additionally, the x-term needs to match the result of multiplying out the factors.
B. (x -1)(2x +5) = 2x^2 +3x -5 . . . . . . . . . wrong x-term (not -3x)
C. (x +1)(2x -5) = 2x^2 -3x -5 . . . . . . . . . matches the given f(x)
The factors of C are zero when x=-1, x=5/2.
C and then D because when you go outside and it’s cold then you know it’s cold
The answer is: Each bag of flour weighs 1,32 kg.
If we the total weight of the bags is given, and we know both the number of bags of flour and sugar, and we also know the weight of each bag of sugar, then we have to find the unknown, which is X. 30 times X plus 4 times the weight of a bag of sugar would equal 42.6kg. Next step is to put the unknown on one side and the known values on the other side. We have 30 times X equals 42.6 minus 4 times 0.75.
To find X we need to divide the value with 30, or to sum up
30X + 4*0.75 = 42.6
30X + 3 = 42.6
X = (42.6 - 3) / 30
X = 1.32 kg
No solution of the system of equations y = -2x + 5 and -5y = 10x + 20 ⇒ 2nd answer
Step-by-step explanation:
Let us revise the types of solutions of a system of linear equations
- One solution
- No solution when the coefficients of x and y in the two equations are equal and the numerical terms are different
- Infinitely many solutions when the coefficients of x , y and the numerical terms are equal in the two equations
∵ y = -2x + 5
- Add 2x to both sides
∴ 2x + y = 5 ⇒ (1)
∵ -5y = 10x + 20
- Subtract 10x from both sides
∴ -10x - 5y = 20
- Divide both sides by -5
∴ 2x + y = -4 ⇒ (2)
∵ The coefficient of x in equation (1) is 2
∵ The coefficient of x in equation (2) is 2
∴ The coefficients of x in the two equations are equal
∵ The coefficient of y in equation (1) is 1
∵ The coefficient of y in equation (2) is 1
∴ The coefficients of y in the two equations are equal
∵ The numerical term in equation (1) is 5
∵ The numerical term in equation (2) is -4
∴ The numerical terms are different
From the 2nd rule above
∴ No solution of the system of equations
No solution of the system of equations y = -2x + 5 and -5y = 10x + 20
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Answer:
9 x 100 + 8 x 10 + 7 x 1000 = 7,980
