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3 years ago

6

A. one solution B. infinitely many solutions C. no solution

1 answer:

kodGreya [7K]3 years ago

3 0

It should be A-one solution

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Umnica [9.8K]

Answer:

<h3> The last x=-5 or x=-2</h3>

Step-by-step explanation:

$x^2+7x+10=0\qquad\implies\quad a=1\,,\ b=7\,,\ c=10\\\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-7\pm\sqrt{7^2-4(1)(10)}}{2(1)}=\dfrac{-7\pm\sqrt{49-40}}{2}=\dfrac{-7\pm\sqrt9}{2}\\\\ x_1=\dfrac{-7+3}2=\dfrac{-4}2=-2\,,\qquad x_1=\dfrac{-7-3}2=\dfrac{-10}2=-5$

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4 years ago

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3 years ago

Solve for the variable<br> --12x = -15<br> Round to the hundredths place, if needed.

EleoNora [17]

Answer:

1.25

Step-by-step explanation:

-12x = -15

12x = 15

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4 years ago