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Andrei [34K]
3 years ago
15

Determine the value of variables a, b, and c that make each equation true.

Mathematics
1 answer:
dybincka [34]3 years ago
4 0

Corrected Question

Determine the values of a, b and c that make each equation true.

(x^a)^6=\dfrac{1}{x^{30}} \\\\(x^{-7})^{-4}=x^b\\\\(x^{-2})^c=x^{22}

Answer:

a=-5, b=28 and c=-11

Step-by-step explanation:

To solve for a,b and c, we apply the following laws of indices

\dfrac{1}{x^y}=x^{-y} \\\\(x^m)^n=x^{m X n}\\\\$If x^m=x^n,$ then m=n

Therefore

(x^a)^6=\dfrac{1}{x^{30}}\\x^{a*6}=x^{-30}\\6a=-30\\a=-5

To solve for b

(x^{-7})^{-4}=x^b\\x^{-7*-4}=x^b\\x^{28}=x^b\\b=28

To solve for c

(x^{-2})^c=x^{22}\\x^{-2*c}=x^{22}\\-2c=22\\c=-11

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Answer:

0.160275

Step-by-step explanation:

P(5 time heads) =P(fair penny and 5 time heads + weighted penny and  5 time heads)

probability of fair penny = 99/100 (as one is removed)

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probability of weighted penny = 1/100

probability of heads for this penny = 90% = 0.9

substituting, we have

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hence from Bayes theorem

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Read 2 more answers
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