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Andrei [34K]
3 years ago
15

Determine the value of variables a, b, and c that make each equation true.

Mathematics
1 answer:
dybincka [34]3 years ago
4 0

Corrected Question

Determine the values of a, b and c that make each equation true.

(x^a)^6=\dfrac{1}{x^{30}} \\\\(x^{-7})^{-4}=x^b\\\\(x^{-2})^c=x^{22}

Answer:

a=-5, b=28 and c=-11

Step-by-step explanation:

To solve for a,b and c, we apply the following laws of indices

\dfrac{1}{x^y}=x^{-y} \\\\(x^m)^n=x^{m X n}\\\\$If x^m=x^n,$ then m=n

Therefore

(x^a)^6=\dfrac{1}{x^{30}}\\x^{a*6}=x^{-30}\\6a=-30\\a=-5

To solve for b

(x^{-7})^{-4}=x^b\\x^{-7*-4}=x^b\\x^{28}=x^b\\b=28

To solve for c

(x^{-2})^c=x^{22}\\x^{-2*c}=x^{22}\\-2c=22\\c=-11

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Answer:

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a^-1 = 1/a

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Answer:

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Step-by-step explanation:

This is what we do.

We first express the first equation in the form;

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Thus we have;

4y = 3x -7

divide through by 4

y = 3/4x -7/4

Thus the slope here is the coefficient of x which is 3/4

Now, since the lines are parallel, it means that their slopes are equal

So the slope of the other line too is 3/4

We now use the point slope form to find the equation of this other line

Mathematically, that would be;

y-y1 = m(x-x1)

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Substituting this into the point slope equation, we have;

y-(-2) = 3/4(x-(-4))

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take cube root of both sides

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