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3 years ago

Please help I don’t understand this.

Mathematics

1 answer:

tresset_1 [31]3 years ago

3 0

The average rate of change of g(x) over the interval [2, 8] is given by

(g (8) - g (2)) / (8 - 2)

In other words, it's the slope of the line through the points (2, g (2)) and (8, g (8)).

Use the definition of the function to evaluate it at the points in the numerator:

• 8 ≥ 4, so using the second piece, g (8) = -0.5(8) + 8 = 4

• 2 < 4, so g (2) = 5(2) + 1 = 11

Then the average rate of change is

(g (8) - g (2)) / (8 - 2) = (4 - 11) / 6 = -7/6

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Use the figure to the right to find the value of PT. T is the midpoint of PQ.

vichka [17]

Answer:

Step-by-step explanation:

Given that T is the midpoint of line PQ, segments PT = 5x + 2, and TQ = 7x - 6 that are formed would be equidistant or congruent. PT = TQ.

Therefore:

$5x + 2 = 7x - 6$

Let's find the value of x

Rearrange the equation, so that the terms having x would be on your left, while those without x would be on your right.

$5x - 7x = - 2 - 6$

$-2x = -8$

Divide both sides by -2

$x = 4$

Plug in the value of x into the expression, 5x + 2, to find PT.

PT = 5(4) + 2 = 22.

8 0

3 years ago

C 70 mm 24 mm What is the length of the hypotenuse?

Anna11 [10]

Answer:

i think the hypotenuse 86 hope this help mark brainliest

Step-by-step explanation:

5 0

4 years ago

HELP!!!! I’LL GIVE THE BRIANLIEST TO WHOEVER GETS IT RIGHT!!!!

Leto [7]

Answer:

13 units

Step-by-step explanation:

D is at (1,6) and C is at (-4,-6)

The distance is found by

d = sqrt(( y2-y1)^2+ (x2-x1)^2))

= sqrt( ( -6-6)^2 + (-4-1)^2)

= sqrt( -12^2 + -5^2)

= sqrt( 144+ 25)

= sqrt( 169)

= 13

6 0

3 years ago

Order 56656, 67445, 9199

gayaneshka [121]

Answer: Least to greatest: 9199, 56656, 67445

Greatest to least: 67445, 56656, 9199

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Help me please ;-;!!!!! Use a coordinate grid to create a map of a town with at least five different locations, such as a house,

Sholpan [36]

A. Our diagram have six location: my house (2,1), a movie theater (5,3), the school (6,6), the police station (3,-2), the airport (-3,3), and the mall (-2,-3)

B. Distance between my house and the movie theater:
To calculate the distance we are going to use the points (2,1) and (5,3) to create a right triangle with tow legs of measures 3 and 2; the hypotenuse of the right triangle will be the distance between my house and the movie theater.
Using the Pythagorean theorem:
$d^2=3^2+2^2$
$d^2=9+4$
$d^2=13$
$d= \sqrt{13}$
We can conclude that the distance between my house and the movie theater is $\sqrt{13}$

Our second distance is the distance between the police station and the airport:
This time we are using the points (3,-2) and (-3,3) to create a right triangle with legs of measures 6 and 5; the hypotenuse of our triangle will be the the distance between our points:
$d^2=6^2+5^2$
$d^2=36+25$
$d^2=61$
$d= \sqrt{61}$
We can conclude that the distance between the police station and the airport is $\sqrt{61}$

C. Distance form the park to the Fire Station:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance from the park to the Fire Station is $\sqrt{10}$

Distance from the stadium to the mall:
$d^2=2^2+1^2$
$d^2=4+1$
$d^2=5$
$d= \sqrt{5}$
We can conclude that the distance from the stadium to the mall is $\sqrt{5}$

D. What is the distance between your house and the mall?
Answer:
$d^2=4^2+4^2$
$d^2=16+16$
$d^2=32$
$d= \sqrt{32}$
$d=4 \sqrt{2}$
We can conclude that the distance between my house and the mall is $4 \sqrt{2}$

What is the distance between the movie theater and the school?
answer:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance between the movie theater and the school is $\sqrt{10}$

7 0

3 years ago