Answer:
17%
Step-by-step explanation:
1,500 + 300 = 1,800
300/1,800 ≈ 17%
Answer:
Step-by-step explanation:
400yd($2304/192yd)=$4800
Answer:
Step-by-step explanation:
How to Find Outliers Using the Interquartile Range(IQR)
Step 1: Find the IQR, Q1(25th percentile) and Q3(75th percentile). ...
Step 2: Multiply the IQR you found in Step 1 by 1.5: ...
Step 3: Add the amount you found in Step 2 to Q3 from Step 1: ...
Step 3: Subtract the amount you found in Step 2 from Q1 from Step 1:
Let's see what the options look like when we multiply the expressions in brackets:
(first, i multiply both parts of the second bracked by the first part of the first bracket, and then the same with the second part of the first bracket:
<span>(1) (3x - 3)(x - 2))
3x2 +6x -3x +6// this is not correct
(2) (3x + 3)(x - 2) </span>
3x2-6x+3x-6//this is not correct
(3)
3(x + 1)(x - 2)
3(x2-2x+x-2)//simplifying:
3(x2-x-2)//multiplying:
3x2-3x-6)
- so this is not correct either
(4) 3(x - 1)(x - 2)
3(x2-2x - x + 2)
3(x2-3x +2)
3x2-9x +6 - well, here is our winner!
Answer:
See below.
Step-by-step explanation:
Here's an example to illustrate the method:
f(x) = 3x^2 - 6x + 10
First divide the first 2 terms by the coefficient of x^2 , which is 3:
= 3(x^2 - 2x) + 10
Now divide the -2 ( in -2x) by 2 and write the x^2 - 2x in the form
(x - b/2)^2 - b/2)^2 (where b = 2) , which will be equal to x^2 - 2x in a different form.
= 3[ (x - 1)^2 - 1^2 ] + 10 (Note: we have to subtract the 1^2 because (x - 1)^2 = x^2 - 2x + 1^2 and we have to make it equal to x^2 - 2x)
= 3 [(x - 1)^2 -1 ] + 10
= 3(x - 1)^2 - 3 + 10
= <u>3(x - 1)^2 + 7 </u><------- Vertex form.
In general form the vertex form of:
ax^2 + bx + c = a [(x - b/2a)^2 - (b/2a)^2] + c .
This is not easy to commit to memory so I suggest the best way to do these conversions is to remember the general method.
