$900+ $288( interest after 8 years)= $1, 188( total balance)
Answer:
Abundance of isotope 79Br=51% and abundance of 81Br=49%
Step-by-step explanation:
We are given that
Mass of 79Br=78.9183 u
Mass of 81Br=80.9163 u
Average atomic mass of bromine=79.90 u
We have to find the relative abundance of the two bromine isotopes.
Let x be the abundance of 79Br
Then , abundance of 81Br isotopes=1-x
Average atomic mass=Mass of isotope(abundance of isotope)+Mass of other isotope(abundance of other isotope)
Using the formula
Percentage of isotope with abundance 0.51=%
Abundance of other isotope=1-0.51=0.49
Percentage of other isotope with abundance 0.49=%
Answer:14 balls did not hit the target.
Step-by-step explanation:
Since 30% did, you would have to do 70% of 20.
For this parabola we have:
f ( 0 ) = 8
and : f ( 1 ) = 24
In the first equation ( A) :
f ( 0 ) = - 16 * ( 0 - 1 )² + 24 = - 16 * 1 + 24 = 8 ( correct )
f ( 1 ) = - 16 * ( 1 - 1 )² + 24 = 24 ( correct )
For B:
f ( 0 ) = - 16 * ( 0 + 1 )² + 24 = - 16 + 24 = 8 ( correct )
f ( 1 ) = - 16 * ( 1 + 1 )² + 24 = - 16 * 4 + 24 = - 64 + 24 = 40 ( false )
For C:
f ( 0 ) = - 16 * ( 0 - 1 )² - 24 = - 16 - 24 = - 40 ( false )
f ( 1 ) = - 16 * ( 1 - 1 )² - 24 = - 24 ( false )
For D:
f ( 0 ) = - 16 * ( 0 + 1 )² - 24 = - 16 - 24 = - 40 ( false )
f ( 1 ) = - 16 * ( 1 - 1 )² - 24 = - 24 ( false )
Answer:
A ) f ( t ) = - 16 * ( t - 1 )² + 24