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shtirl [24]
2 years ago
9

Help im stuck and my pullcrap ahh teacher not her to help and she got me do ixls

Mathematics
1 answer:
marysya [2.9K]2 years ago
3 0

Answer:

c=4

Step-by-step explanation:

c=23

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May someone help me with this quick math problem
vekshin1

Hello,

The correct answer is D) 2

Median: To find the Median, place the numbers you are given in value order and find the middle number. Example: find the Median of {13, 23, 11, 16, 15, 10, 26}. Put them in order: {10, 11, 13, 15, 16, 23, 26} The middle number is 15, so the median is 15. (If there are two middle numbers, you average them.)

The median number of trips taken to the food store in 1 week is 2.

4 - 2 = 2

Hope this helps!!!! :)



8 0
3 years ago
At the end of 10 basketball games, a teams mean score is 35 points per game. At the end of 11 games, their mean score has gone d
morpeh [17]

Their total points for the first 10 games were

(10) x (35) = 350 total .

Their total points after 11 games were

(11) x (33) = 363 total .

They must have scored (363 - 350) = 13 points in that 11th game.

I hate to say it, but these kids and their coach are in the wrong game.

4 0
3 years ago
Write the standard equation for the circle
saw5 [17]

Answer:

The standard form of a circle's equation is (x-h)² + (y-k)² = r² where (h,k) is the center and r is the radius.

Step-by-step explanation:

3 0
2 years ago
What is the degree of the polynomial 2x3 - 3x2 + 4x + 5
tia_tia [17]
With polynomials the degree is the highest power x or whatever the variable is raised to. In this case, the degree is 3 since the highest power x is raised to is x^3
4 0
3 years ago
What is the factored form of 64g^3+8
vivado [14]
\bf \textit{difference and sum of cubes}
\\\\
a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad
(a+b)(a^2-ab+b^2)= a^3+b^3 
\\\\
a^3-b^3 = (a-b)(a^2+ab+b^2)\qquad
(a-b)(a^2+ab+b^2)= a^3-b^3\\\\
-------------------------------\\\\
64g^3+8\implies 4^3g^3+8\implies (4g)^3+2^3
\\\\\\
(4g+2)[(4g)^2-(4g)(2)+2^2]\implies (4g+2)[(4^2g^2)-8g+4]
\\\\\\
(4g+2)(16g^2-8g+4)
3 0
3 years ago
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