Answer:
It will cost $700 to play the entire schedule.
Step-by-step explanation:
Given : ![N(x)=x^2-x](https://tex.z-dn.net/?f=N%28x%29%3Dx%5E2-x)
To Find : A softball league has 5 teams, each of which play the others twice. If the league pays $35 per game, how much will it cost to play the entire schedule?
Solution:
Equation for total no. of games when all the teams play each other twice is ![N(x)=x^2-x](https://tex.z-dn.net/?f=N%28x%29%3Dx%5E2-x)
Now we are given that A softball league has 5 teams, each of which play the others twice.
So, Substitute x = 5 in the given equation
![N(x)=5^2-5](https://tex.z-dn.net/?f=N%28x%29%3D5%5E2-5)
![N(x)=20](https://tex.z-dn.net/?f=N%28x%29%3D20)
So, The total no. of games = 20
Cost for 1 game = $35
So, cost for 20 games = ![35 \times 20 = 700](https://tex.z-dn.net/?f=35%20%5Ctimes%2020%20%3D%20700)
Hence it will cost $700 to play the entire schedule.
Answer:
that anzwer will be (9) ok
Let x = discount rate
Equate:
$80(1-x) = $60
Solve for x:
1-x = 60/80
1-x = 3/4
x = 1 - 3/4
x = 1/4 or 0.25
x = 25%
The answer is 2 3/4 or 2.75
Ratio of amount of change to original shown as a percent.