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vazorg [7]
3 years ago
7

The system shown is O inconsistent • equivalent consistent

Mathematics
2 answers:
stepladder [879]3 years ago
8 0

Answer:

This is pogers

Step-by-step explanation:

What is ur minecraft usernaem

nikitadnepr [17]3 years ago
3 0

Answer:

consistent  

A consistent and independent solution to a system of linear equations is one point

A consistent and dependent solution to a system of linear equations is where they are the same line ( they could also be called equivalent)

An inconsistent solution is where there is no solution, the lines do not cross

Since the lines cross at exactly one point, this is a consistent and dependent solution

The solution is at x = 3  ( 3 units to the right of the origin)

and y = 2 ( 2 units up from the origin)

Step-by-step explanation:

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Which statement is true about the equations-3x 4y 12 and tx 1?
nydimaria [60]

We need to solve -3x+4y=12 for x

Let's start by adding -4y to both sides

-3x+4y-4y=12-4y

-3x=-4y+12

x = (-4y+12)/-3

x= 4/3 y -4

Now substitute 4/3 y -4 for x in 1/4 x - 1/3 y =1

1/4 x -1/3 y =1

1/4 (4/3 y -4) -1/3 y =1

Use the distributive property

(1/4)(4/3 y) + (1/4)(-4) -1/3 y =1

1/3 y -1 - 1/3 y =1

Now combine like terms

(1/3y -1/3y) + (-1) =1

= -1

-1 = 1

Now add 1 to both sides

0=2

So there are no Solutions

The answer is C


I hope that's help Will :)

7 0
3 years ago
Help please! Ty! Ratios
Kamila [148]

Answer:

Ratios to roses to lilies....6:9

Reduced.....2:3

Step-by-step explanation:

Pretty simple doesn't need explaining

8 0
3 years ago
Write the first five terms of the arithmetic sequence. a4 = 22, a10 = 64
dedylja [7]
Hello :
the general term is : 
an = a1+(n-1)×d  
or : an = ap +(n-p)×d......d is common diffrence
let : n=10 and p= 4
a10 =  a4 +(10-4)×d
64 = 22 + 6d
6d =  42
d= 7
conclusion :
a4 = 22
a3 = 22-7=15
a2=15-7=8
a1= 8-7=1
<span>the first five terms : 1 , 8 , 15 , 22</span>

4 0
3 years ago
A sample of 20 joint specimens of a particular type gave a sample mean proportional limit stress of 8.41 mpa and a sample standa
nignag [31]

For this problem, the confidence interval is the one we are looking for. Since the confidence level is not given, we assume that it is 95%.

 

The formula for the confidence interval is: mean ± t (α/2)(n-1) * s √1 + 1/n


Where:

<span>
</span>

α= 5%


α/2 = 2.5%


t 0.025, 19 = 2.093 (check t table)


n = 20


df = n – 1 = 20 – 1 = 19

So plugging in our values:


8.41 ± 2.093 * 0.77 √ 1 + 1/20


= 8.41 ± 2.093 * 0.77 (1.0247)


= 8.41 ± 2.093 * 0.789019


= 8.41 ± 1.65141676


<span>= 6.7586 < x < 10.0614</span>

3 0
3 years ago
What is the 109th term of the arithmetic sequence {963, 936, 909, 882, …}?
tatyana61 [14]

Answer:

D. a109=-1,953

8 0
3 years ago
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