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s2008m [1.1K]
3 years ago
6

Solve x2 – 64 = 0. Isolate x2: x2 = 64 Apply the square root property of equality: StartRoot x squared EndRoot = plus or minus S

tartRoot 64 EndRoot Isolate the variable:
Mathematics
2 answers:
lianna [129]3 years ago
6 0

x=B(8) x=C(-8)

taken on e2020 :)

Archy [21]3 years ago
3 0

Answer:

8, -8

Step-by-step explanation:

I took the assignment on edge :)

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. The larger of two numbers is 7 less than twice the
Ganezh [65]

Answer:

x = 2y - 7

x + y = 47

substitute x

2y - 7 + y = 47

3y = 54

y = 18

x = 2x18 - 7

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4 0
3 years ago
Y=x+ 5 <br>y = 6<br>HELP!!<br>Solve this system of equation algerbraically.​
kati45 [8]

Answer:

x = 1

Step-by-step explanation:

plug y = 6 on to the equation y =x + 5

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5 0
3 years ago
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Merta reports that 74% of its trains are on time. A check of 60 randomly selected trains shows that 38 of them arrived on time.
kenny6666 [7]

Answer:

No, the on-time rate of 74% is not correct.

Solution:

As per the question:

Sample size, n = 60

The proportion of the population, P' = 74% = 0.74

q' = 1 - 0.74 = 0.26

We need to find the probability that out of 60 trains, 38 or lesser trains arrive on time.

Now,

The proportion of the given sample, p = \frac{38}{60} = 0.634

Therefore, the probability is given by:

P(p\leq 0.634) = [\frac{p - P'}{\sqrt{\frac{P'q'}{n}}}]\leq [\frac{0.634 - 0.74}{\sqrt{\frac{0.74\times 0.26}{60}}}]

P(p\leq 0.634) = P[z\leq -1.87188]

P(p\leq 0.634) = P[z\leq -1.87] = 0.0298

Therefore, Probability of the 38 or lesser trains out of 60 trains to be on time is 0.0298 or 2.98 %

Thus the on-time rate of 74% is incorrect.

6 0
2 years ago
What is the answer to 3(5)​
zmey [24]

Answer: 15

Step-by-step explanation:

3x5=15

4 0
3 years ago
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katovenus [111]
In a circle The measurement of a CENTRAL ANGLE (vertex C) is equal to the measurement of the arc intercepted:

65x-4 = 3x+120 ===> 62x=124 & x= 2, hence the arc = 2
5 0
3 years ago
Read 2 more answers
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