All categories

3 years ago

Can you help me please

Mathematics

1 answer:

IRINA_888 [86]3 years ago

8 0

Answer:

find its radii with diameter

You might be interested in

What's the rule? X10 5 25 y 41 21 101

mario62 [17]

It looks to me like y = 4x + 1

3 0

3 years ago

Triangle ABC what is the measurement of Angle C on degrees if Angle A is 32.8° and Angle is 80°.

svp [43]

Answer:

10.8°degrees

Step-by-step explanation:

please click the heart and rate excellent and brainleist to ❤☺️☻♨️♨️☻☺️❤

7 0

3 years ago

Question in image. :)

quester [9]

a. f(a) =5a+12

we have 1. a=6

Therefore, where ever we find a we'll substitute in 6

f(6) =5(6) +12

6f=30+12

6f=42

so therefore 1. a=6 will match c on the right

2. a=2

f(2) =5(2) +12

2f = 10+12

2f = 22

therefore 2. a=2 will match a on the right

3. a=4

f(4) =5(4) +12

4f=20+12

4f=32

therefore 3. a=4 will match d on the right

4. a=5

f(5) =5(5) +12

5f=25+12

5f=37

therefore 4. a=5 will match b on the right

7 0

3 years ago

Factor completely x3 - y3

stealth61 [152]

Answer:

$(x-y)(x^2+xy+y^2)$

Step-by-step explanation:

$x^3 - y^3=(x-y)(x^2+xy+y^2)$

8 0

3 years ago

The total number of people at a football game was 5600. Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

rewona [7]

Answer:

1100 field-side tickets and 4500 end-zone tickets.

Step-by-step explanation:

Let x represent number of field side tickets and y represent number of end-zone tickets.

We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:

$x+y=5600...(1)$

$y=5600-x...(1)$

We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

Cost of x field side tickets would be $40x$ and cost of y end-zone tickets would be $20y$ .

The total amount of money received for the tickets was $134000. We can represent this information in an equation as:

$40x+20y=134000...(2)$

Upon substituting equation (1) in equation (2), we will get:

$40x+20(5600-x)=134000$

$40x+112000-20x=134000$

$20x+112000=134000$

$20x+112000-112000=134000-112000$

$20x=22000$

$\frac{20x}{20}=\frac{22000}{20}$

$x=1100$

Therefore, 1100 field side tickets were sold.

Upon substituting $x=1100$ in equation (1), we will get:

$y=5600-1100$

$y=4500$

Therefore, 4500 end-zone tickets were sold.

3 0

3 years ago

Can you help me please ​

Can you help me please