A line passes through the two points (-4,6) and (2,-5). 11x +6y - 80 = 0 is the given line equation.
<h3>What is the slope of a line which passes through points ( p,q) and (x,y)?</h3>Its slope would be:
The slope of parallel lines are same. Slopes of perpendicular lines are negative reciprocal of each other.
The slope m of the line is given as
The equation of a line is
Hence, the equation is 11x +6y - 80 = 0
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Answer:
The standard form of the equation of the circle is .
Step-by-step explanation:
A circle is the set of points in a plane that lie a fixed distance, called the radius, from any point, called the center.
The equation of a circle in standard form is
where <em>r</em> is the radius of the circle, and <em>h</em>, <em>k</em> are the coordinates of its center.
When the center of the circle coincides with the origin , so
We are also told that the circle contains the point (0, 1), so we will use that information to find the radius <em>r</em>.
Therefore, the standard form of the equation of the circle is .