Answer:
The result will be smaller than 2.6s, 16% of the time.
Step-by-step explanation:
This is a normal distribution problem
The standardized score for any value is the value minus the mean then divided by the standard deviation.
z = (x - xbar)/σ
x = the random value = 2.6 s
xbar = mean = the average = 3.4 s
σ = standard deviation = 0.8 s
z = (2.6 - 3.4)/0.8 = - 1
P(x < 2.6) = P(z < - 1) = 1 - P(z ≥ - 1) = 1 - P(z ≤ 1) = 1 - 0.841 = 0.159 = 16%
283
Start by doing multiplication and division from left to right to follow the order of operations.
270 + 12 / 3 + 9
270 + 4 + 9
Now do addition and subtraction from left to right.
274 + 9
283
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Let the number of red, black, green and blue balls be R, B, G, U respectively.
B=R (There are as many black balls as red balls)
G+R=10 so G=10-R (Green balls and red balls should add up to 10)
R+10=U (There should be 10 more blue balls than red balls)
The minimal number of balls is 2, 304 so we have the following inequality:
R+B+G+U≥ 2,304
R+(R)+(10-R)+ (R+10)≥2,304
4R≥2,304
R≥2,304/4=576 so R=576
Answer: 576
