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pogonyaev
3 years ago
8

I need the quartiles, and the medians of this graph!

Mathematics
1 answer:
motikmotik3 years ago
6 0
Median is 30......ñ.ñ
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A population has a mean of 300 and a standard deviation of 70. Suppose a sample of size 125 is selected and is used to estimate
Mrrafil [7]

Answer:

a:  0.8884

b: 0.9934

Step-by-step explanation:

We have µ = 300 and σ = 70.  The sample size, n = 125.  

For the sample to be within 8 units of the population mean, we would have sample values of 292 and 308, so we want to find:

P(292 < x < 308).

We need to find the z-scores that correspond to these values using the given data.  See attached photo 1 for the calculation of these scores.

We have P(292 < x < 308) = 0.8884

Next we want the probability of the sample mean to be within 17 units of the population mean, so we want the values from 283 to 317.  We want to find

P(283 < x < 317)

We need to find the z-scores that correspond to these values.  See photo 2 for the calculation of these scores.

We have P(283 < x < 317) = 0.9934

5 0
3 years ago
(PLEASE HELP ME)
Schach [20]
This right answer is D.
because -65 divided by -13 is 5
8 0
2 years ago
Read 2 more answers
Ms. Ramo's thumb measures 4 cm. Express this length in meters
Natalija [7]

Answer: 0.04 meters

Step-by-step explanation:

Convert cm to meters by dividing the length by 100.

4/100= = 0.04

6 0
3 years ago
Read 2 more answers
please help :( please help :( please help :( please help :( please help :( please help :( please help :( please help :( please h
egoroff_w [7]

Answer:

V= π×r×r×h

DATA

π= 22÷7

r×r =4

h=6

answer= 75.43

7 0
3 years ago
Read 2 more answers
6(m-1) = 3(3m + 2) Show all work
nordsb [41]

Answer:

\boxed{\sf m = -4}

Step-by-step explanation:

\sf Solve \:  for  \: m: \\  \sf \implies 6 (m - 1) = 3 (3 m + 2) \\  \\  \sf Expand \:  out  \: terms \:  of \:  the \:  left  \: hand \:  side: \\  \sf \implies 6 m - 6 = 3 (3 m + 2) \\  \\  \sf Expand \:  out  \: terms  \: of  \: the  \: right \:  hand \:  side: \\  \sf \implies 6 m - 6 = 9 m + 6 \\  \\  \sf Subtract \:  9 m  \: from  \: both  \: sides: \\  \sf \implies (6 m - 9 m) - 6 = (9 m - 9 m) + 6 \\  \\  \sf 6 m - 9 m = -3 m: \\  \sf \implies -3 m - 6 = (9 m - 9 m) + 6 \\  \\  \sf 9 m - 9 m = 0: \\  \sf \implies -3 m - 6 = 6 \\  \\  \sf Add  \: 6 \:  to \:  both  \: sides: \\  \sf \implies (6 - 6) - 3 m = 6 + 6 \\  \\  \sf 6 - 6 = 0: \\  \sf \implies -3 m = 6 + 6 \\  \\  \sf 6 + 6 = 12: \\  \sf \implies -3 m = 12 \\  \\  \sf Divide  \: both  \: sides  \: of \:  -3 m = 12 \:  by \:  -3: \\  \sf \implies  \frac{ - 3m}{ - 3}  =  \frac{12}{ - 3}  \\  \\  \sf \frac{ - 3}{ - 3} = 1: \\  \sf \implies m =  \frac{12}{ - 3}  \\  \\  \sf -  \frac{12}{3}  =  - 4 :  \\  \sf \implies m =  - 4

7 0
3 years ago
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