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Natalija [7]
2 years ago
10

What is the length of the longest side of an isosceles triangle with leg lengths 2x+12 and 5x-9 and base length 6x-2?

Mathematics
1 answer:
Fiesta28 [93]2 years ago
3 0
Your longest length is going to be 40

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Prove that 4x-1 =11,in which the value of x=3​
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Answer:

3

Step-by-step explanation:

substitute where x=3 into the equation

so 4*3-1=11

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Isolate "x" onto one side:

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Solving Linear Equat<br> Solve the linear equation:<br> 3.4 + 2(9.7 – 4.8x) = 61.2
JulijaS [17]

Answer:

Step-by-step explanation:

Simplifying

3.4 + 2(9.7 + -4.8x) = 61.2

3.4 + (9.7 * 2 + -4.8x * 2) = 61.2

3.4 + (19.4 + -9.6x) = 61.2

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22.8 + -9.6x = 61.2

Solving

22.8 + -9.6x = 61.2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-22.8' to each side of the equation.

22.8 + -22.8 + -9.6x = 61.2 + -22.8

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0.0 + -9.6x = 61.2 + -22.8

-9.6x = 61.2 + -22.8

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-9.6x = 38.4

Divide each side by '-9.6'.

x = -4

Simplifying

x = -4

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