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photoshop1234 [79]
3 years ago
12

Select the graph for the solution of the open sentence. Click until the correct graph appears. 5|x| + 3 < 18

Mathematics
1 answer:
netineya [11]3 years ago
5 0

Answer:

see below

Step-by-step explanation:

5|x| + 3 < 18

Subtract 3 from each side

5|x| + 3-3 < 18-3

5|x| < 15

Divide by 5

5|x| /5 < 15/5

|x|  < 3

There are  two solutions for an absolute value, one positive and one negative ( the negative flips the inequality)

x <3  and  x > -3

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PLEASE HELP ME ASAP!! WILL MARK BRAINLIST
Svet_ta [14]

Answer:

for second box 8. for third box 64 to the power 1/3. for fourth box 1 . and for fifth box 64/512 for sixth box 1/64

8 0
3 years ago
Latricia is calculating the volume of a rectangular prism. The area of the base is 12 cubic centimeters. If the prism has a heig
Katena32 [7]

Answer:V=36\ cm^3

Step-by-step explanation:

Given

Area of base of Rectangular prism A=12\ cm^3

height of Prism h=3\ cm

Volume of Rectangular Prism is given by

V=Area\times height

V=12\times 3

V=36\ cm^3

7 0
3 years ago
Let z1 = a1 + b1i, z2 = a2 + b2i, and z3 = a3 + b3i. Prove the folowing using algebra or by showing with vectors.
Svetlanka [38]

Answer:

a)z1 +z2 =z2 + z1 ...proved.

b) z1 + ( z2+ z3 )=(z1+z2)+z3 ... proved.

Step-by-step explanation:

It is given that there are three vectors z1 = a1 + ib1, z2 = a2 + ib2 and z3 = a3 + ib3. Now, we have to prove (a) z1 + z2 = z2 + z1 and (b) z1 + (z2 +z3) = (z1 + z2) + z3.

(a) z1 + z2 = (a1 +ib1) + (a2+ ib2) = (a1 +a2) + i(b1 +b2) {Adding the real and imaginary parts separately}

Again, z2 + z1 =(a2 +ib2) + (a1 +ib1) = (a2 +a1) + i(b2 +b1) {Adding the real and imaginary parts separately}

Hence, z1 +z2 =z2 + z1 {Since, (a1 +a2) = (a2 +a1) and (b1 +b2) = (b2 +b1)}

(b) z1 + ( z2+ z3 ) = [a1 + ib1] + [(a2 + a3 ) + i(b2 + b3 )] = ( a1 + a2 + a3) + i( b1+ b2+b3) {Adding the real and imaginary parts separately}

Again, (z1+z2)+z3 = [(a1+a2) +i(b1+b2)]+[a3+ib3] = ( a1 + a2 + a3) + i( b1+ b2+b3) {Adding the real and imaginary parts separately}

Hence, z1 + ( z2+ z3 )=(z1+z2)+z3 proved.

5 0
3 years ago
Line segments AB and CD intersect at point E. Ray EF extends from point E.
Tom [10]

Answer:

x=29 CEF=103 BEF=58

Step-by-step explanation:

161=3x+16+2x

5x=145

x=29

7 0
3 years ago
Kade solved this problem:
fredd [130]
Parent: 5 child: 9
I’m not completely sure though please let me know if I’m right!
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3 years ago
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