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Trava [24]
2 years ago
13

Lim x tends to π÷2 , then what is the value of (tanx + cotx) ÷ ( tanx - cotx)​

Mathematics
1 answer:
KiRa [710]2 years ago
8 0

(tan(<em>x</em>) + cot(<em>x</em>)) / (tan(<em>x</em>) - cot(<em>x</em>)) = (tan²(<em>x</em>) + 1) / (tan²(<em>x</em>) - 1)

… = (sin²(<em>x</em>) + cos²(<em>x</em>)) / (sin²(<em>x</em>) - cos²(<em>x</em>))

… = -1/cos(2<em>x</em>)

Then as <em>x</em> approaches <em>π</em>/2, the limit is -1/cos(2•<em>π</em>/2) = -sec(<em>π</em>) = 1.

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