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madreJ [45]
3 years ago
13

Jada have a monthly budget for her cell phone bill last month she spent 120% of her budget and the bill was $60 what is Jada mon

thly budget
Mathematics
2 answers:
Damm [24]3 years ago
4 0

Assume that the budget is n.

Now we are given that 120% of the budget is equal to $60.

This means that:

60 = 1.2n

Solve the equation for n to know the budget:

60 = 1.2n

n = 60 / 1.2 = 50

Based on the above calculations, Jada's budget is 50$

-Dominant- [34]3 years ago
4 0

Answer:

58.8

Step-by-step explanation:

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3 years ago
Find the rectangular coordinates of the point that has polar coordinates , 4, −3π/4
kirill115 [55]
Hello : 
 x= r cos<span>θ
 y= r sin</span><span>θ
r = 4   and  </span>θ =<span> −3π/4
cos( </span> −3π/4 )  = cos(  3π/4 ) = cos ( π - <span>π/4) = - cos (</span><span>π/4)= - </span><span>√2/2
</span>sin(  −3π/4 )  =  -  sin(  3π/4 ) = - sin ( π - π/4) = -sin (π/4)= - √2/2
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6 0
4 years ago
What 2+2 x10+2X2+10=
erastova [34]

Answer:

36

Step-by-step explanation:

Use PEMDAS:

2*10 is 20

2*2 is 4

So the equation is now

2+20+4+10=

Now add:

36

Thus the solution is 36

Hope this helps!

4 0
2 years ago
Read 2 more answers
Which of the following is the the correct factorization of this trinomial.
sergey [27]
-3x^2-10x-8 = - (3x^2 +10x+8 ) = - (3x^2 +6x +4x+8) =\\ \\=-[3x(x+2)+4(x+2)]= - (3x+4) (x+2) \\ \\Answer : \ c)\ \ \ -(3x+4)(x+2)


6 0
3 years ago
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You are given a list of students names and their test scores. Design a pseudocode that does the following:(a) Calculates the ave
Rashid [163]

Answer:

List_of_students = {};    //Structure array that contains the scores of students and Names

Number_of_students = size(List_of_students);

Average_score ;   //Variable Stores average score

Below_Average = [];   //That is initially filled with zeros  

Highest_score ; //Initialize variable to store highest score

for ( i = 0 ; i < Number_of_students; i = i + 1)

{

      Average_score  = Average_score + List_of_students(i);    

     if ( i = 15)

      {

        Average_score  = Average_score / Number_of_students;

      }

}

for ( j = 0; j < Number_of_students ; i = i + 1)

{

    if (   List_of_students(j)  < Average_score)

     {

         print( "student  %name got %score , List_of_students(j),          List_of_students(j) )

     }

}

Compare_Score = 0;   //Variable to compare score

for ( k = 0; K < Number_of_students; k = k+1)

{

     if ( List_of_students(k) => Compare_Score)

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        Compare_Score = List_of_students(k);

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}

Highest_Score = Compare_Score;

Step-by-step explanation:

4 0
3 years ago
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