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Evgesh-ka [11]
3 years ago
10

Which set of ordered pairs satisfies an inverse variation?

Mathematics
1 answer:
Bogdan [553]3 years ago
7 0
The answer that satisfies an inverse variation is J.
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-7x = -28<br> solving one step equations <br> show your work
scoray [572]

Answer:

x=4

Step-by-step explanation:

-7x=-28

-7     -7

x=4

Divide both sides by -7.  A negative divided by a negative will give you a positive. So the answer would be x=4.

3 0
3 years ago
Read 2 more answers
In matrix multiplication, such as AB=C, the columns of B form the rows of C. why is this?
Gnesinka [82]
Let's work with 2-by-2 matrices so we're on the same page. The ideas will work for any appropriate matrices.

From the rule of matrix multiplication, we see:
\left[\begin{array}{cc}a_{11} & a_{12} \\a_{21} & a_{22} \end{array}\right] \left[\begin{array}{cc}b_{11} & b_{12} \\b_{21} & b_{22} \end{array}\right] = \left[\begin{array}{cc} a_{11}b_{11} + a_{12}b_{21} & a_{11}b_{12} + a_{12}b_{22} \\ a_{21}b_{11} + a_{22}b_{21} & a_{21}b_{12} + a_{22} b_{22} \end{array}\right]
As you noted, we see the columns of B contributing to the rows of C. The question is, why would we ever have defined matrix multiplication this way?

Here's a nontraditional way of feeling this connection. We can define matrix multiplication as "adding multiplication tables." A multiplication table is made by starting with a column and a row. For example,
\begin{array}{ccc} {} & 1 & 2 \\ 1 & {} & {} \\ 2 & {} & {} \end{array}
We then fill this table in by multiplying the row and column entries:
\begin{array}{ccc} {} & [1] & [2] \\ 1| &1 & 2 \\ 2| & 2 &4 \end{array}
It's then reasonable to say that given two matrices A and B, we can construct multiplication tables by taking the columns of A and pairing them with the rows of B:
\left[\begin{array}{cc}a_{11} & a_{12} \\a_{21} & a_{22} \end{array}\right] \left[\begin{array}{cc}b_{11} & b_{12} \\b_{21} & b_{22} \end{array}\right]

= \begin{array}{cc} {} & \left[\begin{array}{cc} b_{11} & b_{12}\end{array} \right]\\ \left[\begin{array}{c} a_{11} \\ a_{21} \end{array} \right] \end{array} +\begin{array}{cc} {} & \left[\begin{array}{cc} b_{21} & b_{22}\end{array} \right]\\ \left[\begin{array}{c} a_{12} \\ a_{22} \end{array} \right] \end{array}

= \left[\begin{array}{cc} a_{11} b_{11} & a_{11} b_{12} \\ a_{21} b_{11} & a_{21} b_{12} \end{array} \right] + \left[\begin{array}{cc} a_{12} b_{21} & a_{12} b_{22} \\ a_{22} b_{21} & a_{22} b_{22} \end{array} \right]

Adding these matrices together, we get the exact same expression as the traditional definition. 




5 0
4 years ago
Which of these representations could model the same relationship? Select ALL that apply
Alex17521 [72]

Answers:

<h2>*Top left chart</h2><h2 /><h2>*y=2x-1</h2><h2 /><h2>*Bottom left graph</h2><h2 /><h2>*Store is having a sale. every item is $2 and you get $1 off your total</h2>

I hope this helps and good luck!

4 0
3 years ago
Read 2 more answers
What is the distance around a circle called?
Marianna [84]
Circumference is the answer 
7 0
3 years ago
Read 2 more answers
Solve for x this is hard:(
OleMash [197]

Answer:

x is 9

Step-by-step explanation:

since they are vertical angles, they are congruent. We make an equation putting each one behind the equal sign (7x+3=10x-24) and we solve.

8 0
3 years ago
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