Answer:
4 pi cm
Step-by-step explanation:
Chance to draw 7: 4 out of 52
chance to draw 1st queen: 4 out of 51
chance to draw 2nd queen: 3 out of 50
total chance = multiplication of

times

times


pretty miserable change... apox 1 out of 2762, but still much better than any lottery ticket
Answer:
9.06
Step-by-step explanation:
If a number is positive, Leila's theory that 75% of a number will always be greater than 50% of another number is <em>true</em>;<em> </em>however, if both numbers are negative, or if the number of which she finds 50% is much greater than the number of which she finds 75%, Leila's theory could be incorrect.
This inequality shows that Leila is correct:

(which simplifies to

)
This inequality shows that Leila is incorrect:

(which simplifies to

)
Hope this helps!
Answer:
The absolute number of a number a is written as
|a|
And represents the distance between a and 0 on a number line.
An absolute value equation is an equation that contains an absolute value expression. The equation
|x|=a
Has two solutions x = a and x = -a because both numbers are at the distance a from 0.
To solve an absolute value equation as
|x+7|=14
You begin by making it into two separate equations and then solving them separately.
x+7=14
x+7−7=14−7
x=7
or
x+7=−14
x+7−7=−14−7
x=−21
An absolute value equation has no solution if the absolute value expression equals a negative number since an absolute value can never be negative.
The inequality
|x|<2
Represents the distance between x and 0 that is less than 2
Whereas the inequality
|x|>2
Represents the distance between x and 0 that is greater than 2
You can write an absolute value inequality as a compound inequality.
−2<x<2
This holds true for all absolute value inequalities.
|ax+b|<c,wherec>0
=−c<ax+b<c
|ax+b|>c,wherec>0
=ax+b<−corax+b>c
You can replace > above with ≥ and < with ≤.
When solving an absolute value inequality it's necessary to first isolate the absolute value expression on one side of the inequality before solving the inequality.
Step-by-step explanation:
Hope this helps :)