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viktelen [127]
3 years ago
7

In the diagram, GB = 2x + 3..

Mathematics
2 answers:
zaharov [31]3 years ago
5 0

<u>Answer-</u>

\boxed{\boxed{GB=15\ units}}

<u>Solution-</u>

From the attachment,

AD = AE, so FA is a median.

BD = BF, so BE is a median.

CF = CE, so DC is a median.

And G is the centroid.

From the properties of centroid, we know that

The centroid divides each median in a ratio of 2:1

So,

\Rightarrow FG:AG=2:1

\Rightarrow \dfrac{FG}{AG}=\dfrac{2}{1}

\Rightarrow FG=2\times AG

\Rightarrow 5x=2\times (x+9)

\Rightarrow 5x=2x+18

\Rightarrow 3x=18

\Rightarrow x=6

So, GB will be 2(6)+3=15 units

ZanzabumX [31]3 years ago
4 0

Answer:  The correct option is (C) 15 units.

Step-by-step explanation:  We are given to find the length of GB in the figure.

Given that

FG = 5x  and  GA = x + 9.

From the figure, we note that DC, EB and FA are the medians of ΔDEF drawn from the vertices D, E and F respectively.

Since, the medians intersect at the point G, so G is the centroid of ΔDEF.

We know that the centroid divides each median of a triangle in the ratio 2 : 1, so we have

FG:GA=2:1\\\\\\\Rightarrow \dfrac{FG}{GA}=\dfrac{2}{1}\\\\\\\Rightarrow \dfrac{5x}{x+9}=2\\\\\\\Rightarrow 5x=2x+18\\\\\Rightarrow 3x=18\\\\\Rightarrow x=6.

Therefore, the length of GB will be

GB=2x+3=2\times6+3=12+3=15~\textup{units}.

Thus, the length of GB is 15 units.

Option (C) is correct.

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Step-by-step explanation:

Let's determine angle b first

Angle b=20° (alternate angles)

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X² =8.8²+2.4²-2(8.8)(2.4)cos20

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X²= 43.51

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2.4/sin b = 6.6/sin20

(2.4*sin20)/6.6= sin b

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Angle c= 180-20-7.146

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Question # 13

Answer:

The required equation for the given function is <em>y = 4sin(x/2+2π/3) -2 , as shown attached graph diagram.</em>

<em>Step-by-step explanation: </em>

As the general sine function is given by

y=asin(bx+c)+d.......[A]

  • amplitude = a
  • period = 2π ÷ b
  • Phase shift = -c ÷ b
  • Vertical shift = d

As in the question,  

  • amplitude = a = 4
  • period = 4π
  • phase shift = -4π/3
  • Vertical shift = d = -2

As  

period = 2π ÷ b  

b = 2π/period

b = 2π/4π ∵ period = 4π

b = 1/2  

Also

Phase shift = -c/b

-4π/3 = -c/b ∵ phase shift = -4π/3

4π/3 = c/b  

c = b × 4π/3  

c = 1/2 × 4π/3  

c = 4π/6  

c = 2π/3

So, putting Amplitude ⇒ a = 4, Vertical shift ⇒ d = -2, b = 1/2 ,  

and c = 2π/3 in Equation [A] would bring us the required equation for the given function.

y=asin(bx+c)+d

y = 4sin(x/2+2π/3)+(-2)

y = 4sin(x/2+2π/3) -2            

<em>Note: The graph is also shown in attached diagram.</em>

                                             Question # 14

<em>Answer:</em>

The required equation for the given function is y = cot(x+π/3)+2, as shown in attached graph diagram.

<em>Step-by-step explanation: </em>

As the general cotangent function is given by

y=acot(bx+c)+d.......[A]

  • amplitude = a
  • period = π ÷ b
  • Phase shift = -c ÷ b
  • Vertical shift = d

As in the question,  

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As  

period = π ÷ b  

b = π/period

b = π/π ∵ period = 4π

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Also

Phase shift = -c/b

-π/3 = -c/b ∵ phase shift = -π/3

π/3 = c/b  

c = b × π/3  

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c = π/3

So, putting vertical shift ⇒ d = 2, b = 1 and   c = π/3 in Equation [A] would bring us the required equation for the given function.

y=acot(bx+c)+d

y = cot(x+π/3)+2

<em>Note: The graph is also shown in attached diagram.</em>

Keywords: amplitude, period , phase shift , vertical shift

Learn more about trigonometric functions of equations from brainly.com/question/2643311

#learnwithBrainly

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Step-by-step explanation:

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