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2 years ago

Xugo hit tht new rank ;0 good job bby

Business

1 answer:

Ne4ueva [31]2 years ago

8 0

Hello!

Um, Okay...

Good Job, for you bby hit a new rank...

Have a great day!

#LearnWithBrainly

$Answer$ :

- TanakaBro

Plus, here is a anime image that might make your day happy. . .

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Walter is a chemistry teacher who earns $50,000 per year, while Jesse is unemployed. Both Walter and Jesse want to go back to sc

katrin2010 [14]

Answer:

No, their economic cost of enrolling in the business program is not the same for both,

Explanation:

The explicit costs of going back to college are the same for Walter and Jesse, e.g. they might be $20,000 per year, or even $30,000 doesn't matter for this analysis. But Walter is currently working as a teacher and that means taht if he decides to go to college, his implicit costs will include the forgone salary as a teacher which is $50,000 per year. Implicit costs are opportunity costs, i.e. additional costs or benefits lost from choosing one activity or investment instead of another alternative.

Since Jesse is not working, whether she goes back to college or not will not affect her income, it will still be $0, but if Walter goes back to college he will lose his salary.

6 0

2 years ago

On January 1, an investment account is worth 50,000. On May 1, the value has increased to 52,000 and 8,000 of new principal is d

Evgesh-ka [11]

The question is incomplete. The complete question is :

On January 1, an investment account is worth 50,000. On May 1, the value has increased to 52,000 and 8,000 of new principal is deposited. At time t, in years, (4/12 < t < 1) the value of the fund has increased to 62,000 and 10,000 is withdrawn. On January 1 of the next year, the investment account is worth 55,000. The approximate dollar-weighted rate of return (using the simple interest approximation) is equal to the time-weighted rate of return for the year. Calculate t.

Solution :

It is given that :

Worth of investment account on 1st Jan = 50,000

Worth of investment account on 1st Jan next year = 55,000

New principal deposited = 8000

Therefore the interest earned = 55,000 - 50,000 - 8,000 + 10,000

= 7,000

Therefore,

$\frac{7000}{\frac{50000+16000}{3-10000(1-t)}}= \frac{52}{50} \frac{62}{60} \frac{55}{52} - 1$

= 0.13667

7000 = 0.13667(55,333.33 - 10000 + 10000t)

$t=\frac{7000-0.13667(45333.33)}{1366.7}$

= 0.5885

Thus, time - weighted rate of the return = 0.5885

4 0

2 years ago

During a recent shopping trip to Target, Carlie noticed that the store offered many Glad products, including many different type

Sauron [17]

Answer: product line

Explanation: In simple words, a product line refers to the process under which a producer groups its related products together. The product could be related on the basis of their use or any other such criteria.

In the given case,Glad was offering variety of different trash bags and food products on a single selling place.

Hence we can conclude that it is an example of product line .

7 0

2 years ago

Collusion occurs when companies agree to drop prices and increase production.

Komok [63]

It’s obviously false you nerd

3 0

2 years ago

A market research company employs a large number of typists to enter data into a computer database. The time it takes for potent

monitta

Answer:

4.75% of the candidates takes more than two hours to learn the computer system.

Explanation:

The relevant information to solve the problem is:

1. The time it takes to learn follows a Normal distribution

2. The mean is 90 minutes

3. The standard deviation is 18 minutes

4. The question is What proportion of candidates takes more than two hours to learn the computer system?

Then, you shall calculate the Z-score and use a standard distribution table to look up the Z-score and the corresponding probability.

Repeating myself from a recent answer, "there are two types of standard distribution tables: tables that show values that represent the AREA to the LEFT of the Z-score, and tables that show values that represent the AREA to the RIGHT of the Z-score".

1. First, calculate the Z-score:

$Z-score=\frac{x-mean}{standard\text{ }deviation}$

$x=2hours=120min$

$Z-score=\frac{120-90}{18}\approx 1.67$

2. Use the table that represents the area to the right of the mean to find the ratio of typists that have a Z-score greater than 1.67.

$Probability=0.0475=4.75\%$

Therefore, 4.75% of the candidates takes more than two hours to learn the computer system.

4 0

2 years ago