The first side of a triangle measures 4 in. less than the second side, the third side is 3 in. more than the first side, and the
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Answer:
C. H0: µD = 0, HA: µD <0
Step-by-step explanation:
We assume that the paired sample data are simple random samples and that the differences have a distribution that is approximately normal. So for this case is better apply a paired t test.
A paired t-test is used to compare two population means where you have two samples in which observations in one sample can be paired with observations in the other sample. For example if we have Before-and-after observations (This problem) we can use it.
Let put some notation
x=test value for pretest , y = test value for posttest
x: 66, 94, 87, 84, 76, 88
y: 75, 100, 93, 85, 75, 90
The system of hypothesis for this case are:
Null hypothesis:
Alternative hypothesis:
Because the difference D is defined as Pretest-Postest. And we want to see if the postets score is higher than the pretest with th training.
The first step is calculate the difference and we obtain this:
d: -9, -6, -6, -1, 1, -2
The second step is calculate the mean difference
The third step would be calculate the standard deviation for the differences, and we got:
The 4 step is calculate the statistic given by :
The next step is calculate the degrees of freedom given by:
Now we can calculate the p value, since we have a left tailed test the p value is given by:
The p value is lower than the significance level assumed , so then we can conclude that we can reject the null hypothesis. So we can say that the differences between Pretest and Posttest
are less than 0.
Answer: They should order 160 steak, 80 lobster and 260 chicken. The total cost for the meals would be $4460
Step-by-step explanation:
The cruiser will have 400 passangers on board. By taking into account that the cruise line decided to buy 25% more of meals than bookings, we can conclude that in order to calculate the ammount of meals they will order, we have to take the number of passangers on board, 400, and add to it 25% more. So the number of meal orders will be 400 + (1/4 * 400) = 500.
Let's use the letter S to simbolize the ammount of steak they should buy, with L the ammount of lobster, and with C the ammount of chicken. The sum of those ammounts should be 500, so we deduce this formula
we can replace C with 500 - S - L. Since at least forty percent of the passangers will have steak dinner and at least twenty percent will have lobster, we obtain this relations:
We note the total cost of the meals (in $). The value of
will depend on the values of S and L. Using the information we are given about the cost of each dinner, and recalling that C was 500- S - L, we can represent
by this formula
Which is equal to
We want to minimaze the value of , since 3*S + 6*L will get bigger as we use bigger values of S and L, then we will be in a good position if we take the values of S and L as low as possible.
With the restriction we obtained, the lowest values of S and L we can take are 160 and 80 respectively; so we take those values. In conclusion
- S = 160 (number of steak)
- L = 80 (number of lobster)
- C = 500-160-80 = 260 (number of chicken)
The total cost of the meals is