Answer:
Probability that average height would be shorter than 63 inches = 0.30854 .
Step-by-step explanation:
We are given that the average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 inches.
Also, a random sample of 4 women from this population is taken and their average height is computed.
Let X bar = Average height
The z score probability distribution for average height is given by;
Z =
~ N(0,1)
where,
= population mean = 64 inches
= standard deviation = 4 inches
n = sample of women = 4
So, Probability that average height would be shorter than 63 inches is given by = P(X bar < 63 inches)
P(X bar < 63) = P(
<
) = P(Z < -0.5) = 1 - P(Z <= 0.5)
= 1 - 0.69146 = 0.30854
Hence, it is 30.85% likely that average height would be shorter than 63 inches.
Circumference=2pir=<span>2∗3.14∗5.1</span><span>=30.028=30.03.</span>
Answer:
(1,-2) and (0,-5) (There are an infinite amount more)
Step-by-step explanation:
The easiest way to find solutions is to plug in an x value. Let's try 1:
y = 3(1) - 5⇒y = 3 - 5⇒y = -2
(1,-2)
Let's try 0:
y = 3(0) - 5⇒y = 0 - 5 ⇒y = -5
(0,-5)