Answer:
Step-by-step explanation:
<u>Initial coordinates and transformations:</u>
- (x, y) → (4x, 4y) → (3x, 3y)
- A(-1, -1) → A'(-4, -4) → A''(-3, -3)
- B(1, 1) → B'(4, 4) → B''(3, 3)
- C(2, 0) → C'(8, 0) → C''(6, 0)
We know that
Applying the law of cosines
c²=a²+b²-2*a*b*cos
C------> cos C=[a²+b²-c²]/[2*a*b]
in this problem
a=7.6 in
b=8.6 in
c=7.4 in
C=angle V
cos C=[7.6²+8.6²-7.4²]/[2*7.6*8.6]----> 0.5887
C=arc cos (0.5887)--------> C=53.93°-------> C=53.9°
the answer is
angle V is 53.9°
Answer:
Step-by-step explanation:
cant remember what this method is called but
change the second equation to be y = something
x + y = 10
y = -x + 10
plug in this y= in the first equation to get x
4x -2(-x + 10) = 4
4x + 2x -20 = 4
6x = 24
x = 4
then plug in the x we found into the original second equation
4 + y = 10
y = 6
so your ordered pair would be (4,6)
hope this helps <3
1/2×12m×18.2m=109.2m2
109.2m2÷21.8m÷1/2=10m(nearest whole number)
h=10m
