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Daniel [21]
3 years ago
9

Choose the most appropriate strategy and then use it to solve the quadratic equation.

Mathematics
1 answer:
dsp733 years ago
7 0

 (x-8) ^ 2 = 121
 
(x-8) = + / - root (121)
 x = 8 +/- root (121)
 The solutions are:
 
x1 = 8 + root (121)
 
x2 = 8 - root (121)
 2a ^ 2 = 8a-6
 2a ^ 2-8a + 6 = 0
 a ^ 2-4a + 3 = 0
 (a-1) (a-3) = 0
 The solutions are:
 
a1 = 1
 
a2 = 3
 x ^ 2 + 12x + 36 = 4
 x ^ 2 + 12x + 36-4 = 0
 x ^ 2 + 12x + 32 = 0
 (x + 4) (x + 8) = 0
 The solutions are:
 
x1 = -8
 
x2 = -4
 x ^ 2-x + 30 = 0
 
x = (- b +/- root (b ^ 2 - 4 * a * c)) / 2 * a
 x = (- (- 1) +/- root ((- 1) ^ 2 - 4 * (1) * (30))) / 2 * (1)
 x = (1 +/- root (1 - 120))) / 2
 x = (1 +/- root (-119))) / 2
 x = (1 +/- root (119) * i)) / 2
 The solutions are:
 
x1 = (1 + root (119) * i)) / 2
 
x2 = (1 - root (119) * i)) / 2
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We have

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2D + 36.15 - 9D = 15.50;

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Murljashka [212]
Length - l

Width - w

Given,

Perimeter = 60 

2(l +w) = 60

l + w = 30 

l = 30 - w

Given,

l = 3w

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What are the intercepts of the line 3x – 15y = 60?   A. x-intercept: –4; y-intercept: 20   B. x-intercept: –3; y-intercept: 15  
geniusboy [140]
<span>3x – 15y = 60

y-intercept x = 0</span>
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answer :

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