E-filing<span> technical information - acceptable native (or </span>source<span>) electronic </span>file<span> format types. ... Whenever possible, the electronic </span>source<span> files used to create the PDF should be uploaded after the PDF in the same </span>filing<span>. Multiple </span>source<span> files can be uploaded in the same </span>filing<span>.</span>
Answer:
Option a. int max = aList.get(0); for (int count = 1; count < aList.size(); count++) { if (aList.get(count) > max) { max = aList.get(count); } }
is the correct code snippet.
Explanation:
Following is given the explanation for the code snippet to find largest value in an integer array list aList.
- From the array list aList, very first element having index 0 will be stored in the variable max (having data type int).
- By using for starting from count =1 to count = size of array (aList), we will compare each element of the array with first element of the array.
- If any of the checked element get greater from the first element, it gets replaced in the variable max and the count is increased by 1 so that the next element may be checked.
- When the loop will end, the variable max will have the greatest value from the array aList.
i hope it will help you!
I believe the answer to this is server virtualization.
Collaborative software or groupware.
