C. 38 ATP
<span>In the presence of oxygen, one
glucose molecule has the energy to make up to 38 ATP. The ATP production is
determined by the following steps, (-2 ATP) glycolysis preparatory phase, (7-9
ATP) glycolysis pay-off phase, (5 ATP) oxidative decarboxylation of pyruvate
and (20 ATP) Krebs cycle. One glucose which has 38 ATP hence was the summation
of all the process mentioned that took place. All these process take place under the
cellular function of cellular respiration. </span>
Answer:
1/2
Explanation:
This question involves a single gene coding for feather color in chickens. The black allele (B) is incompletely dominant over the white allele (W). This means that the allele B will not mask the phenotypic expression of allele W, hence, a third intermediate blue phenotype (BW) will be produced.
According to the question, if two blue chickens are crossed i.e. BW × BW, the gametes B and W will be produced by each parent. Using these gametes in a punnet square (see attached image), the following offsprings will be produced:
BB, BW and WW in the ratio 1:2:1
BB is black, BW is blue, WW is white. Hence, the probability of producing a blue chicken from this cross is 1/2.
A) Light dependent and light independent/Dark reaction
I guess I would say b or d. Because concluded results change over time with better technology and some solutions dont work.