Someone please help!!!!!!

Rasputen and his three buddies are splitting a giant 18 inch cookie. But notice 1/4 of it is missing. If each person gets the sa

frozen [14]

Answer:

Each of them will get 3.375 inches of cookie.

Step-by-step explanation:

Rasputen and his three buddies are splitting a giant 18 inches cookie.

But they notice that $\frac{1}{4}$ th of it is missing.

So, the actual length of the cookie is $18[1-\frac{1}{4} ]=18 \times \frac{3}{4}=13.5$ inches.

If all the four of them get the same amount of the giant cookie then each of them will get $\frac{13.5}{4} = 3.375$ inches of cookie. (Answer)

8 0

3 years ago

Can somebody help me solve this?

Nookie1986 [14]

Answer:

z = 3.2 units

Step-by-step explanation:

sin 76°/z = sin 51°/2.6

cross-multiply to get:

z·(sin 51°) = 2.6·(sin 76°)

z = 2.6·(sin 76°) ÷ (sin 51°)

z = 3.2

3 0

3 years ago

Choose either Multiplication and Division

Sliva [168]

Answer:

multiplication and divisioni gusss cause area will be give amd all" × " u have to put in "÷" fiorm

6 0

3 years ago

Read 2 more answers

2. In a class 70 students, 44 like Bookkeeping, 36 like- Commerce, and 17 like both bookkeeping and commere How many student lik

tigry1 [53]

Answer:

17

Step-by-step explanation:

you said that in the problem lol

5 0

2 years ago

Read 2 more answers

A person's blood glucose level and diabetes are closely related. Let x be a random variable measured in milligrams of glucose pe

soldier1979 [14.2K]

Using the normal distribution, it is found that:

a) 0.8599 = 85.99% probability that x is more than 60.

b) 0.1788 = 17.88% probability that x is less than 110.

c) 0.6811 = 68.11% probability that x is between 60 and 110.

d) 0.0643 = 6.43% probability that x is greater than 125.

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

The mean is of 87, thus $\mu = 87$ .
The standard deviation is of 25, thus $\sigma = 25$ .

Item a:

This probability is 1 subtracted by the p-value of Z when X = 60, thus:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{60 - 87}{25}$

$Z = -1.08$

$Z = -1.08$ has a p-value of 0.1401.

1 - 0.1401 = 0.8599

0.8599 = 85.99% probability that x is more than 60.

Item b:

This probability is the p-value of Z when X = 110, thus:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{110 - 87}{25}$

$Z = 0.92$

$Z = 0.92$ has a p-value of 0.8212.

1 - 0.8212 = 0.1788.

0.1788 = 17.88% probability that x is less than 110.

Item c:

This probability is the p-value of Z when X = 110 subtracted by the p-value of Z when X = 60.

From the previous two items, 0.8212 - 0.1401 = 0.6811.

0.6811 = 68.11% probability that x is between 60 and 110.

Item d:

This probability is 1 subtracted by the p-value of Z when X = 125, thus:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{125 - 87}{25}$

$Z = 1.52$

$Z = 1.52$ has a p-value of 0.9357.

1 - 0.9357 = 0.0643.

0.0643 = 6.43% probability that x is greater than 125.

A similar problem is given at brainly.com/question/24863330

7 0

3 years ago