Find m∠LKE. m∠LKJ = 150° m∠LKE = (x + 32)° m∠EKJ = (x + 94)° A) 40° B) 44° C) 46° Eliminate D) 48°
2 answers:
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Answer:
Solution : (36, 42)
Step-by-step explanation:
It mention that the image is dilated by a scale factor of 6, and hence we will have to multiply each coordinate by 6 to receive the dilated point. Here we only want the dilation of point B,
B' = (6 6, 7
6) = (36, 42)
If quadrilateral ABCD is dilated by a scale factor of 6, then the coordinates of point B' are (36, 42).
Answer:
There is a 24.51% probability that he weight of a bag will be greater than the maximum allowable weight of 50 pounds.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by
After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.
In this problem
Suppose that the weights of airline passenger bags are normally distributed with a mean of 47.88 pounds and a standard deviation of 3.09 pounds, so
What is the probability that the weight of a bag will be greater than the maximum allowable weight of 50 pounds?
That is
So
has a pvalue of 0.7549.
This means that .
We also have that
There is a 24.51% probability that he weight of a bag will be greater than the maximum allowable weight of 50 pounds.