Suppose a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 h

Question

3 years ago

8

Suppose a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 h

oles each.
What is the probability the golfer got zero or one hole-in-one during a single game?
What is the probability the golfer got exactly two holes-in-one during a single game?
What is the probability the golfer got six holes-in-one during a single game?

Mathematics

1 answer:

vladimir2022 [97] · Answer 1 · 2022-11-14T11:01:55+03:00

A) The probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.

B) The probability the golfer got exactly two holes-in-one during a single game is 8.57%.

C) The probability the golfer got six holes-in-one during a single game is close to 0%.

<h2 /><h2><u>How to determine probabilities</u></h2>

Since a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 holes each, to determine A) what is the probability the golfer got zero or one hole -in-one during a single game, B) what is the probability the golfer got exactly two holes-in-one during a single game, and C) what is the probability the golfer got six holes-in-one during a single game , the following calculations must be performed:

1 - 0.12 = 0.88
0.88 ^ 17 = 0.1138
0.88 ^ 18 = 0.1001

Therefore, the probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.

0.88 ^ 18 - 0.12 ^ 2 = X
0.0857 = X

Therefore, the probability the golfer got exactly two holes-in-one during a single game is 8.57%.

0.12 ^ 6 x 0.88 ^ 12 = X
0.0000000001 = X

Therefore, the probability the golfer got six holes-in-one during a single game is close to 0%.

Learn more about probabilities in brainly.com/question/25273534