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Sergio039 [100]
3 years ago
7

When a sample of aqueous hydrochloric acid was neutralized with aqueous sodium hydroxide in a calorimeter, the temperature of 14

8.3 g of water surrounding the reaction increased by 5.43 degrees * C . If the specific heat of water is 1.00 cal/(g C) , calculate the quantity of energy in calories involved in this neutralization reaction. (Ignore the heat gain by the calorimeter)
Chemistry
1 answer:
lora16 [44]3 years ago
4 0

Answer:

805.3cal

Explanation:

All neutralization reactions produce heat when occurs.

The reaction of HCl with NaOH produce heat increasing the aqueous medium in 5.43°C. The equation of the released energy is:

Q = S×m×ΔT

<em>Where Q is heat, </em>

<em>S is specific heat of the solution (1.00cal/g°C)</em>

<em>m is mass of water: 148.3g</em>

<em>ΔT is change in temperature: 5.43°C</em>

<em />

Q = 1.00cal/g°C×148.3g×5.43°C

Q = 805.3cal

<em />

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Hello!

In this case, for this acid-base reaction which also known as a neutralization because sulfuric acid is neutralized with sodium hydroxide, we can write the undergoing chemical reaction as shown below:

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